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Chapters
2: Functions
▶ 3: Inverse Trigonometric Functions
4: Algebra of Matrices
5: Determinants
6: Adjoint and Inverse of a Matrix
7: Solution of Simultaneous Linear Equations
8: Continuity
9: Differentiability
10: Differentiation
11: Higher Order Derivatives
12: Derivative as a Rate Measurer
13: Differentials, Errors and Approximations
14: Mean Value Theorems
15: Tangents and Normals
16: Increasing and Decreasing Functions
17: Maxima and Minima
18: Indefinite Integrals
19: Definite Integrals
20: Areas of Bounded Regions
21: Differential Equations
22: Algebra of Vectors
23: Scalar Or Dot Product
24: Vector or Cross Product
25: Scalar Triple Product
26: Direction Cosines and Direction Ratios
27: Straight Line in Space
28: The Plane
29: Linear programming
30: Probability
31: Mean and Variance of a Random Variable
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Solutions for Chapter 3: Inverse Trigonometric Functions
Below listed, you can find solutions for Chapter 3 of CBSE, Karnataka Board PUC RD Sharma for Mathematics Volume 1 and 2 [English] Class 12.
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.01 [Pages 6 - 7]
Find the principal value of the following:
`sin^-1(-sqrt3/2)`
Find the principal value of the following:
`sin^-1(cos (2pi)/3)`
Find the principal value of the following:
`sin^-1((sqrt3-1)/(2sqrt2))`
Find the principal value of the following:
`sin^-1((sqrt3+1)/(2sqrt2))`
Find the principal value of the following:
`sin^-1(cos (3pi)/4)`
Find the principal value of the following:
`sin^-1(tan (5pi)/4)`
`sin^-1 1/2-2sin^-1 1/sqrt2`
`sin^-1{cos(sin^-1 sqrt3/2)}`
Find the domain of the following function:
`f(x)=sin^-1x^2`
Find the domain of the following function:
`f(x) = sin^-1x + sinx`
Find the domain of the following function:
`f(x)sin^-1sqrt(x^2-1)`
Find the domain of the following function:
`f(x)=sin^-1x+sin^-1 2x`
If `sin^-1 x + sin^-1 y+sin^-1 z+sin^-1 t=2pi` , then find the value of x2 + y2 + z2 + t2
If `(sin^-1x)^2 + (sin^-1y)^2+(sin^-1z)^2=3/4pi^2,` find the value of x2 + y2 + z2
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.02 [Page 10]
Find the domain of definition of `f(x)=cos^-1(x^2-4)`
Find the domain of `f(x) =2cos^-1 2x+sin^-1x.`
Find the domain of `f(x)=cos^-1x+cosx.`
Find the principal values of the following:
`cos^-1(-sqrt3/2)`
Find the principal values of the following:
`cos^-1(-1/sqrt2)`
Find the principal values of the following:
`cos^-1(sin (4pi)/3)`
Find the principal values of the following:
`cos^-1(tan (3pi)/4)`
For the principal value, evaluate of the following:
`cos^-1 1/2 + 2 sin^-1 (1/2)`
For the principal value, evaluate of the following:
`sin^-1(-1/2)+2cos^-1(-sqrt3/2)`
For the principal value, evaluate of the following:
`sin^-1(-sqrt3/2)+cos^-1(sqrt3/2)`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.03 [Page 14]
Find the principal value of the following:
`tan^-1(1/sqrt3)`
Find the principal value of the following:
`tan^-1(-1/sqrt3)`
Find the principal value of the following:
`tan^-1(cos pi/2)`
Find the principal value of the following:
`tan^-1(2cos (2pi)/3)`
For the principal value, evaluate of the following:
`tan^-1(-1)+cos^-1(-1/sqrt2)`
For the principal value, evaluate of the following:
`tan^-1{2sin(4cos^-1 sqrt3/2)}`
Evaluate the following:
`tan^-1 1+cos^-1 (-1/2)+sin^-1(-1/2)`
Evaluate the following:
`tan^-1(-1/sqrt3)+tan^-1(-sqrt3)+tan^-1(sin(-pi/2))`
Evaluate the following:
`tan^-1(tan (5pi)/6)+cos^-1{cos((13pi)/6)}`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.04 [Page 18]
Find the principal value of the following:
`sec^-1(-sqrt2)`
Find the principal value of the following:
`sec^-1(2)`
Find the principal value of the following:
`sec^-1(2sin (3pi)/4)`
Find the principal value of the following:
`sec^-1(2tan (3pi)/4)`
For the principal value, evaluate the following:
`tan^-1sqrt3-sec^-1(-2)`
For the principal value, evaluate the following:
`sin^-1(-sqrt3/2)-2sec^-1(2tan pi/6)`
Find the domain of `sec^(-1)(3x-1)`.
Find the domain of `sec^(-1) x-tan^(-1)x`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.05 [Page 21]
Find the principal value of the following:
`cosec^-1(-sqrt2)`
Find the principal value of the following:
cosec-1(-2)
Find the principal value of the following:
`\text(cosec)^-1(2/sqrt3)`
Find the principal value of the following:
`cosec^-1(2cos (2pi)/3)`
Find the set of values of `cosec^-1(sqrt3/2)`
For the principal value, evaluate the following:
`sin^-1(-sqrt3/2)+\text{cosec}^-1(-2/sqrt3)`
For the principal value, evaluate the following:
`sec^-1(sqrt2)+2\text{cosec}^-1(-sqrt2)`
For the principal value, evaluate the following:
`sin^-1[cos{2\text(cosec)^-1(-2)}]`
For the principal value, evaluate the following:
`cosec^-1(2tan (11pi)/6)`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.06 [Page 24]
Find the principal value of the following:
`cot^-1(-sqrt3)`
Find the principal value of the following:
`cot^-1(sqrt3)`
Find the principal value of the following:
`cot^-1(-1/sqrt3)`
Find the principal value of the following:
`cot^-1(tan (3pi)/4)`
Find the domain of `f(x)=cotx+cot^-1x`
Evaluate the following:
`cot^-1 1/sqrt3-\text(cosec)^-1(-2)+sec^-1(2/sqrt3)`
Evaluate the following:
`cot^-1{2cos(sin^-1 sqrt3/2)}`
Evaluate the following:
`\text(cosec)^-1(-2/sqrt3)+2cot^-1(-1)`
Evaluate the following:
`tan^-1(-1/sqrt3)+cot^-1(1/sqrt3)+tan^-1(sin(-pi/2))`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.07 [Pages 42 - 43]
`sin^-1(sin pi/6)`
`sin^-1(sin (7pi)/6)`
`sin^-1(sin (5pi)/6)`
`sin^-1(sin (13pi)/7)`
`sin^-1(sin (17pi)/8)`
`sin^-1{(sin - (17pi)/8)}`
`sin^-1(sin3)`
`sin^-1(sin4)`
`sin^-1(sin12)`
`sin^-1(sin2)`
Evaluate the following:
`cos^-1{cos(-pi/4)}`
Evaluate the following:
`cos^-1{cos (5pi)/4}`
Evaluate the following:
`cos^-1{cos ((4pi)/3)}`
Evaluate the following:
`cos^-1{cos (13pi)/6}`
Evaluate the following:
`cos^-1(cos3)`
Evaluate the following:
`cos^-1(cos4)`
Evaluate the following:
`cos^-1(cos5)`
Evaluate the following:
`cos^-1(cos12)`
Evaluate the following:
`tan^-1(tan pi/3)`
Evaluate the following:
`tan^-1(tan (6pi)/7)`
Evaluate the following:
`tan^-1(tan (7pi)/6)`
Evaluate the following:
`tan^-1(tan (9pi)/4)`
Evaluate the following:
`tan^-1(tan1)`
Evaluate the following:
`tan^-1(tan2)`
Evaluate the following:
`tan^-1(tan4)`
Evaluate the following:
`tan^-1(tan12)`
Evaluate the following:
`sec^-1(sec pi/3)`
Evaluate the following:
`sec^-1(sec (2pi)/3)`
Evaluate the following:
`sec^-1(sec (5pi)/4)`
Evaluate the following:
`sec^-1(sec (7pi)/3)`
Evaluate the following:
`sec^-1(sec (9pi)/5)`
Evaluate the following:
`sec^-1{sec (-(7pi)/3)}`
Evaluate the following:
`sec^-1(sec (13pi)/4)`
Evaluate the following:
`sec^-1(sec (25pi)/6)`
Evaluate the following:
`\text(cosec)^-1(\text{cosec} pi/4)`
Evaluate the following:
`cosec^-1(cosec (3pi)/4)`
Evaluate the following:
`cosec^-1(cosec (6pi)/5)`
Evaluate the following:
`cosec^-1(cosec (11pi)/6)`
Evaluate the following:
`cosec^-1(cosec (13pi)/6)`
Evaluate the following:
`cosec^-1{cosec (-(9pi)/4)}`
Evaluate the following:
`cot^-1(cot pi/3)`
Evaluate the following:
`cot^-1(cot (4pi)/3)`
Evaluate the following:
`cot^-1(cot (9pi)/4)`
Evaluate the following:
`cot^-1(cot (19pi)/6)`
Evaluate the following:
`cot^-1{cot (-(8pi)/3)}`
Evaluate the following:
`cot^-1{cot ((21pi)/4)}`
Write the following in the simplest form:
`cot^-1 a/sqrt(x^2-a^2),| x | > a`
Write the following in the simplest form:
`tan^-1{x+sqrt(1+x^2)},x in R `
Write the following in the simplest form:
`tan^-1{sqrt(1+x^2)-x},x in R`
Write the following in the simplest form:
`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`
Write the following in the simplest form:
`tan^-1{(sqrt(1+x^2)+1)/x},x !=0`
Write the following in the simplest form:
`tan^-1sqrt((a-x)/(a+x)),-a<x<a`
Write the following in the simplest form:
`tan^-1(x/(a+sqrt(a^2-x^2))),-a<x<a`
Write the following in the simplest form:
`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`
Write the following in the simplest form:
`sin^-1{(sqrt(1+x)+sqrt(1-x))/2},0<x<1`
Write the following in the simplest form:
`sin{2tan^-1sqrt((1-x)/(1+x))}`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.08 [Page 54]
Evaluate the following:
`sin(sin^-1 7/25)`
Evaluate the following:
`sin(cos^-1 5/13)`
Evaluate the following:
`sin(tan^-1 24/7)`
Evaluate the following:
`sin(sec^-1 17/8)`
Evaluate the following:
`cosec(cos^-1 3/5)`
Evaluate the following:
`sec(sin^-1 12/13)`
Evaluate the following:
`tan(cos^-1 8/17)`
Evaluate the following:
`cot(cos^-1 3/5)`
Evaluate the following:
`cos(tan^-1 24/7)`
Prove the following result
`tan(cos^-1 4/5+tan^-1 2/3)=17/6`
Prove the following result
`cos(sin^-1 3/5+cot^-1 3/2)=6/(5sqrt13)`
Prove the following result-
`tan^-1 63/16 = sin^-1 5/13 + cos^-1 3/5`
Prove the following result
`sin(cos^-1 3/5+sin^-1 5/13)=63/65`
Solve: `cos(sin^-1x)=1/6`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.09 [Pages 58 - 59]
Evaluate:
`cos{sin^-1(-7/25)}`
Evaluate:
`sec{cot^-1(-5/12)}`
Evaluate:
`cot{sec^-1(-13/5)}`
Evaluate:
`tan{cos^-1(-7/25)}`
Evaluate:
`cosec{cot^-1(-12/5)}`
Evaluate:
`cos(tan^-1 3/4)`
Evaluate: `sin{cos^-1(-3/5)+cot^-1(-5/12)}`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.10 [Page 66]
Evaluate:
`cot(sin^-1 3/4+sec^-1 4/3)`
Evaluate:
`sin(tan^-1x+tan^-1 1/x)` for x < 0
Evaluate:
`sin(tan^-1x+tan^-1 1/x)` for x > 0
Evaluate:
`cot(tan^-1a+cot^-1a)`
Evaluate:
`cos(sec^-1x+\text(cosec)^-1x)`,|x|≥1
If `cos^-1x + cos^-1y =pi/4,` find the value of `sin^-1x+sin^-1y`
If `sin^-1x+sin^-1y=pi/3` and `cos^-1x-cos^-1y=pi/6`, find the values of x and y.
If `cot(cos^-1 3/5+sin^-1x)=0`, find the values of x.
If `(sin^-1x)^2+(cos^-1x)^2=(17pi^2)/36,` Find x
`sin(sin^-1 1/5+cos^-1x)=1`
`sin^-1x=pi/6+cos^-1x`
`4sin^-1x=pi-cos^-1x`
`tan^-1x+2cot^-1x=(2x)/3`
`5tan^-1x+3cot^-1x=2x`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.11 [Page 82]
Prove the following result:
`tan^-1 1/7+tan^-1 1/13=tan^-1 2/9`
Prove the following result:
`sin^-1 12/13+cos^-1 4/5+tan^-1 63/16=pi`
Prove the following result:
`tan^-1 1/4+tan^-1 2/9=sin^-1 1/sqrt5`
Find the value of `tan^-1 (x/y)-tan^-1((x-y)/(x+y))`
Solve the following equation for x:
`tan^-1 2x+tan^-1 3x = npi+(3pi)/4`
Solve the following equation for x:
tan−1(x + 1) + tan−1(x − 1) = tan−1`8/31`
Solve the following equation for x:
tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x
Solve the following equation for x:
`tan^-1((1-x)/(1+x))-1/2 tan^-1x` = 0, where x > 0
Solve the following equation for x:
cot−1x − cot−1(x + 2) =`pi/12`, x > 0
Solve the following equation for x:
tan−1(x + 2) + tan−1(x − 2) = tan−1 `(8/79)`, x > 0
Solve the following equation for x:
`tan^-1 x/2+tan^-1 x/3=pi/4, 0<x<sqrt6`
Solve the following equation for x:
`tan^-1((x-2)/(x-4))+tan^-1((x+2)/(x+4))=pi/4`
Solve the following equation for x:
`tan^-1(2+x)+tan^-1(2-x)=tan^-1 2/3, where x< -sqrt3 or, x>sqrt3`
Solve the following equation for x:
`tan^-1 (x-2)/(x-1)+tan^-1 (x+2)/(x+1)=pi/4`
Sum the following series:
`tan^-1 1/3+tan^-1 2/9+tan^-1 4/33+...+tan^-1 (2^(n-1))/(1+2^(2n-1))`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.12 [Page 89]
Evaluate: `cos(sin^-1 3/5+sin^-1 5/13)`
`sin^-1 63/65=sin^-1 5/13+cos^-1 3/5`
`sin^-1 5/13+cos^-1 3/5=tan^-1 63/16`
`(9pi)/8-9/4sin^-1 1/3=9/4sin^-1 (2sqrt2)/3`
Solve the following:
`sin^-1x+sin^-1 2x=pi/3`
Solve the following:
`cos^-1x+sin^-1 x/2=π/6`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.13 [Page 92]
If `cos^-1 x/2+cos^-1 y/3=alpha,` then prove that `9x^2-12xy cosa+4y^2=36sin^2a.`
Solve the equation `cos^-1 a/x-cos^-1 b/x=cos^-1 1/b-cos^-1 1/a`
Solve `cos^-1sqrt3x+cos^-1x=pi/2`
Prove that: `cos^-1 4/5+cos^-1 12/13=cos^-1 33/65`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.14 [Pages 115 - 116]
Evaluate the following:
`tan{2tan^-1 1/5-pi/4}`
Evaluate the following:
`tan 1/2(cos^-1 sqrt5/3)`
Evaluate the following:
`sin(1/2cos^-1 4/5)`
Evaluate the following:
`sin(2tan^-1 2/3)+cos(tan^-1sqrt3)`
Prove that:
`2sin^-1 3/5=tan^-1 24/7`
`tan^-1 1/4+tan^-1 2/9=1/2cos^-1 3/2=1/2sin^-1(4/5)`
`tan^-1 2/3=1/2tan^-1 12/5`
`tan^-1 1/7+2tan^-1 1/3=pi/4`
`sin^-1 4/5+2tan^-1 1/3=pi/2`
`2sin^-1 3/5-tan^-1 17/31=pi/4`
`2tan^-1 1/5+tan^-1 1/8=tan^-1 4/7`
`2tan^-1 3/4-tan^-1 17/31=pi/4`
`2tan^-1(1/2)+tan^-1(1/7)=tan^-1(31/17)`
`4tan^-1 1/5-tan^-1 1/239=pi/4`
If `sin^-1 (2a)/(1+a^2)-cos^-1 (1-b^2)/(1+b^2)=tan^-1 (2x)/(1-x^2)`, then prove that `x=(a-b)/(1+ab)`
Prove that
`tan^-1((1-x^2)/(2x))+cot^-1((1-x^2)/(2x))=pi/2`
Prove that
`sin{tan^-1 (1-x^2)/(2x)+cos^-1 (1-x^2)/(2x)}=1`
If `sin^-1 (2a)/(1+a^2)+sin^-1 (2b)/(1+b^2)=2tan^-1x,` Prove that `x=(a+b)/(1-ab).`
Show that `2tan^-1x+sin^-1 (2x)/(1+x^2)` is constant for x ≥ 1, find that constant.
Find the value of the following:
`tan^-1{2cos(2sin^-1 1/2)}`
Find the value of the following:
`cos(sec^-1x+\text(cosec)^-1x),` | x | ≥ 1
Solve the following equation for x:
`tan^-1 1/4+2tan^-1 1/5+tan^-1 1/6+tan^-1 1/x=pi/4`
Solve the following equation for x:
`3sin^-1 (2x)/(1+x^2)-4cos^-1 (1-x^2)/(1+x^2)+2tan^-1 (2x)/(1-x^2)=pi/3`
Solve the following equation for x:
`tan^-1((2x)/(1-x^2))+cot^-1((1-x^2)/(2x))=(2pi)/3,x>0`
Solve the following equation for x:
`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`
Solve the following equation for x:
`cos^-1((x^2-1)/(x^2+1))+1/2tan^-1((2x)/(1-x^2))=(2x)/3`
Solve the following equation for x:
`tan^-1((x-2)/(x-1))+tan^-1((x+2)/(x+1))=pi/4`
Prove that `2tan^-1(sqrt((a-b)/(a+b))tan theta/2)=cos^-1((a costheta+b)/(a+b costheta))`
Prove that:
`tan^-1 (2ab)/(a^2-b^2)+tan^-1 (2xy)/(x^2-y^2)=tan^-1 (2alphabeta)/(alpha^2-beta^2),` where `alpha=ax-by and beta=ay+bx.`
For any a, b, x, y > 0, prove that:
`2/3tan^-1((3ab^2-a^3)/(b^3-3a^2b))+2/3tan^-1((3xy^2-x^3)/(y^3-3x^2y))=tan^-1 (2alphabeta)/(alpha^2-beta^2)`
`where alpha =-ax+by, beta=bx+ay`
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.15 [Pages 116 - 119]
Write the value of `sin^-1((-sqrt3)/2)+cos^-1((-1)/2)`
Write the difference between maximum and minimum values of sin−1 x for x ∈ [− 1, 1].
If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2,` then write the value of x + y + z.
If x > 1, then write the value of sin−1 `((2x)/(1+x^2))` in terms of tan−1 x.
If x < 0, then write the value of cos−1 `((1-x^2)/(1+x^2))` in terms of tan−1 x.
Write the value of tan−1x + tan−1 `(1/x)`for x > 0.
Write the value of tan−1 x + tan−1 `(1/x)` for x < 0.
What is the value of cos−1 `(cos (2x)/3)+sin^-1(sin (2x)/3)?`
If −1 < x < 0, then write the value of `sin^-1((2x)/(1+x^2))+cos^-1((1-x^2)/(1+x^2))`
Write the value of sin (cot−1 x).
Write the value of
\[\cos^{- 1} \left( \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\].
Write the range of tan−1 x.
Write the value of cos−1 (cos 1540°).
Write the value of sin−1
\[\left( \sin( -{600}°) \right)\].
Write the value of cos\[\left( 2 \sin^{- 1} \frac{1}{3} \right)\]
Write the value of sin−1 (sin 1550°).
Evaluate sin
\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]
Evaluate sin \[\left( \tan^{- 1} \frac{3}{4} \right)\]
Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]
Write the value of cos \[\left( 2 \sin^{- 1} \frac{1}{2} \right)\]
Write the value of cos−1 (cos 350°) − sin−1 (sin 350°)
Write the value of cos2 \[\left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right)\]
If tan−1 x + tan−1 y = `pi/4`, then write the value of x + y + xy.
Write the value of cos−1 (cos 6).
Write the value of sin−1 \[\left( \cos\frac{\pi}{9} \right)\]
Write the value of sin \[\left\{ \frac{\pi}{3} - \sin^{- 1} \left( - \frac{1}{2} \right) \right\}\]
Write the value of tan−1\[\left\{ \tan\left( \frac{15\pi}{4} \right) \right\}\]
Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]
Write the value of \[\tan^{- 1} \frac{a}{b} - \tan^{- 1} \left( \frac{a - b}{a + b} \right)\]
Write the value of cos−1 \[\left( \cos\frac{5\pi}{4} \right)\]
Show that \[\sin^{- 1} (2x\sqrt{1 - x^2}) = 2 \sin^{- 1} x\]
Evaluate: \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]
If \[\tan^{- 1} (\sqrt{3}) + \cot^{- 1} x = \frac{\pi}{2},\] find x.
If \[\sin^{- 1} \left( \frac{1}{3} \right) + \cos^{- 1} x = \frac{\pi}{2},\] then find x.
Write the value of \[\sin^{- 1} \left( \frac{1}{3} \right) - \cos^{- 1} \left( - \frac{1}{3} \right)\]
If 4 sin−1 x + cos−1 x = π, then what is the value of x?
If x < 0, y < 0 such that xy = 1, then write the value of tan−1 x + tan−1 y.
What is the principal value of `sin^-1(-sqrt3/2)?`
Write the principal value of `sin^-1(-1/2)`
Write the principal value of \[\cos^{- 1} \left( \cos\frac{2\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{2\pi}{3} \right)\]
Write the value of \[\tan\left( 2 \tan^{- 1} \frac{1}{5} \right)\]
Write the principal value of \[\tan^{- 1} 1 + \cos^{- 1} \left( - \frac{1}{2} \right)\]
Write the value of \[\tan^{- 1} \left\{ 2\sin\left( 2 \cos^{- 1} \frac{\sqrt{3}}{2} \right) \right\}\]
Write the principal value of `tan^-1sqrt3+cot^-1sqrt3`
Write the principal value of \[\cos^{- 1} \left( \cos680^\circ \right)\]
Write the value of \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]
Write the value of \[\sec^{- 1} \left( \frac{1}{2} \right)\]
Write the value of \[\cos^{- 1} \left( \cos\frac{14\pi}{3} \right)\]
Write the value of \[\cos\left( \sin^{- 1} x + \cos^{- 1} x \right), \left| x \right| \leq 1\]
Wnte the value of the expression \[\tan\left( \frac{\sin^{- 1} x + \cos^{- 1} x}{2} \right), \text { when } x = \frac{\sqrt{3}}{2}\]
Write the principal value of \[\sin^{- 1} \left\{ \cos\left( \sin^{- 1} \frac{1}{2} \right) \right\}\]
The set of values of `\text(cosec)^-1(sqrt3/2)`
Write the value of \[\tan^{- 1} \left( \frac{1}{x} \right)\] for x < 0 in terms of `cot^-1x`
Write the value of `cot^-1(-x)` for all `x in R` in terms of `cot^-1(x)`
Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]
If \[\cos\left( \tan^{- 1} x + \cot^{- 1} \sqrt{3} \right) = 0\] , find the value of x.
Find the value of \[2 \sec^{- 1} 2 + \sin^{- 1} \left( \frac{1}{2} \right)\]
If \[\cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = 0\], find the value of x.
Find the value of \[\cos^{- 1} \left( \cos\frac{13\pi}{6} \right)\]
Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 3 Inverse Trigonometric Functions Exercise 4.16 [Pages 119 - 122]
If \[\tan^{- 1} \left( \frac{\sqrt{1 + x^2} - \sqrt{1 - x^2}}{\sqrt{1 + x^2} + \sqrt{1 - x^2}} \right)\] = α, then x2 =
sin 2 α
sin α
cos 2 α
cos α
The value of tan \[\left\{ \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right\}\] is
`sqrt29/3`
`29/3`
`sqrt3/29`
`3/29`
2 tan−1 {cosec (tan−1 x) − tan (cot−1 x)} is equal to
cot−1 x
cot−1`1/x`
tan−1 x
none of these
If \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]
sin2 α
cos2 α
tan2 α
cot2 α
The positive integral solution of the equation
\[\tan^{- 1} x + \cos^{- 1} \frac{y}{\sqrt{1 + y^2}} = \sin^{- 1} \frac{3}{\sqrt{10}}\text{ is }\]
x = 1, y = 2
x = 2, y = 1
x = 3, y = 2
x = −2, y = −1
If sin−1 x − cos−1 x = `pi/6` , then x =
`1/2`
`sqrt3/2`
`-1/2`
none of these
sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\] is equal to
x
`sqrt(1-x^2`
`1/x`
none of these
The number of solutions of the equation \[\tan^{- 1} 2x + \tan^{- 1} 3x = \frac{\pi}{4}\] is
2
3
1
none of these
If α = \[\tan^{- 1} \left( \tan\frac{5\pi}{4} \right) \text{ and }\beta = \tan^{- 1} \left( - \tan\frac{2\pi}{3} \right)\] , then
4 α = 3 β
3 α = 4 β
α − β = `(7pi)/12`
none of these
The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]
0
1
2
infinite
If x < 0, y < 0 such that xy = 1, then tan−1 x + tan−1 y equals
`pi/2`
`-pi/2`
− π
none of these
\[\text{ If } u = \cot^{- 1} \sqrt{\tan \theta} - \tan^{- 1} \sqrt{\tan \theta}\text{ then }, \tan\left( \frac{\pi}{4} - \frac{u}{2} \right) =\]
`sqrt(tantheta`
`sqrt(cottheta)`
tan θ
cot θ
\[\text{ If }\cos^{- 1} \frac{x}{3} + \cos^{- 1} \frac{y}{2} = \frac{\theta}{2}, \text{ then }4 x^2 - 12xy \cos\frac{\theta}{2} + 9 y^2 =\]
36
36 − 36 cos θ
18 − 18 cos θ
18 + 18 cos θ
If α = \[\tan^{- 1} \left( \frac{\sqrt{3}x}{2y - x} \right), \beta = \tan^{- 1} \left( \frac{2x - y}{\sqrt{3}y} \right),\]
then α − β =
`pi/6`
`pi/3`
`pi/2`
`-pi/3`
Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) =
e5π/18
e13π/18
e−2π/18
none of these
\[\tan^{- 1} \frac{1}{11} + \tan^{- 1} \frac{2}{11}\] is equal to
0
1/2
− 1
none of these
If \[\cos^{- 1} \frac{x}{2} + \cos^{- 1} \frac{y}{3} = \theta,\] then 9x2 − 12xy cos θ + 4y2 is equal to
36
−36 sin2 θ
36 sin2 θ
36 cos2 θ
If tan−1 3 + tan−1 x = tan−1 8, then x =
5
1/5
5/14
14/5
The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is
`(3pi)/5`
`-pi/10`
`pi/10`
`(7pi)/5`
The value of \[\cos^{- 1} \left( \cos\frac{5\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{5\pi}{3} \right)\] is
`pi/2`
`(5pi)/3`
`(10pi)/3`
0
sin \[\left\{ 2 \cos^{- 1} \left( \frac{- 3}{5} \right) \right\}\] is equal to
`6/25`
`24/25`
`4/5`
`-24/25`
If θ = sin−1 {sin (−600°)}, then one of the possible values of θ is
`pi/3`
`pi/2`
`(2pi)/3`
`-(2pi)/3`
If \[3\sin^{- 1} \left( \frac{2x}{1 + x^2} \right) - 4 \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) + 2 \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) = \frac{\pi}{3}\] is equal to
`1/sqrt3`
`-1/sqrt3`
`sqrt3`
`-sqrt3/4`
If 4 cos−1 x + sin−1 x = π, then the value of x is
`2/3`
`1/sqrt2`
`sqrt3/2`
`2/sqrt3`
It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\] (−7), then the value of x is
0
−2
1
2
If \[\cos^{- 1} x > \sin^{- 1} x\], then
\[\frac{1}{\sqrt{2}} < x \leq 1\]
\[0 \leq x < \frac{1}{\sqrt{2}}\]
\[- 1 \leq x < \frac{1}{\sqrt{2}}\]
x > 0
In a ∆ ABC, if C is a right angle, then
\[\tan^{- 1} \left( \frac{a}{b + c} \right) + \tan^{- 1} \left( \frac{b}{c + a} \right) =\]
`pi/3`
`pi/4`
`(5x)/2`
`pi/6`
The value of sin \[\left( \frac{1}{4} \sin^{- 1} \frac{\sqrt{63}}{8} \right)\] is
`1/sqrt2`
`1/sqrt3`
`1/(2sqrt2)`
`1/(3sqrt3)`
\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) =\]
7
6
5
none of these
If tan−1 (cot θ) = 2 θ, then θ =
`+-pi/3`
`+-pi/4`
`+-pi/6`
none of these
If \[\sin^{- 1} \left( \frac{2a}{1 - a^2} \right) + \cos^{- 1} \left( \frac{1 - a^2}{1 + a^2} \right) = \tan^{- 1} \left( \frac{2x}{1 - x^2} \right),\text{ where }a, x \in \left( 0, 1 \right)\] , then, the value of x is
0
`a/2`
a
`(2a)/(1-a^2)`
The value of \[\sin\left( 2\left( \tan^{- 1} 0 . 75 \right) \right)\] is equal to
0.75
1.5
0.96
`sin^-1 1.5`
If x > 1, then \[2 \tan^{- 1} x + \sin^{- 1} \left( \frac{2x}{1 + x^2} \right)\] is equal to
`4tan^-1x`
0
`pi/2`
π
The domain of \[\cos^{- 1} \left( x^2 - 4 \right)\] is
[3, 5]
[−1, 1]
\[\left[ - \sqrt{5}, - \sqrt{3} \right] \cup \left[ \sqrt{3}, \sqrt{5} \right]\]
\[\left[ - \sqrt{5}, - \sqrt{3} \right] \cap \left[ \sqrt{3}, \sqrt{5} \right]\]
The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]
`19/8`
`8/19`
`19/12`
`3/4`
Solutions for 3: Inverse Trigonometric Functions
![RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 chapter 3 - Inverse Trigonometric Functions RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 chapter 3 - Inverse Trigonometric Functions - Shaalaa.com](/images/mathematics-volume-1-and-2-english-class-12_6:3add8ebc78154d0b8720bd9ba95f35a9.jpg)
RD Sharma solutions for Mathematics Volume 1 and 2 [English] Class 12 chapter 3 - Inverse Trigonometric Functions
Shaalaa.com has the CBSE, Karnataka Board PUC Mathematics Mathematics Volume 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. RD Sharma solutions for Mathematics Mathematics Volume 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC 3 (Inverse Trigonometric Functions) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Mathematics Volume 1 and 2 [English] Class 12 chapter 3 Inverse Trigonometric Functions are Properties of Inverse Trigonometric Functions, Basics of Inverse Trigonometric Functions, Domain, Range & Principal Value, Graphs of Inverse Trigonometric Functions, Overview of Inverse Trigonometric Functions.
Using RD Sharma Mathematics Volume 1 and 2 [English] Class 12 solutions Inverse Trigonometric Functions exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in RD Sharma Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board PUC Mathematics Volume 1 and 2 [English] Class 12 students prefer RD Sharma Textbook Solutions to score more in exams.
Get the free view of Chapter 3, Inverse Trigonometric Functions Mathematics Volume 1 and 2 [English] Class 12 additional questions for Mathematics Mathematics Volume 1 and 2 [English] Class 12 CBSE, Karnataka Board PUC, and you can use Shaalaa.com to keep it handy for your exam preparation.
