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Question
Evaluate the following:
`cos^-1(cos3)`
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Solution
We know
`cos^-1(costheta)=thetaif 0<=theta<=pi`
We have
`cos^-1(cos3)=3`
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Is there an error in this question or solution?
Evaluate the following:
`cos^-1(cos3)`
We know
`cos^-1(costheta)=thetaif 0<=theta<=pi`
We have
`cos^-1(cos3)=3`