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2 Tan−1 {Cosec (Tan−1 X) − Tan (Cot−1 X)} is Equal to (A) Cot−1 X (B) Cot−1 1 X (C) Tan−1 X (D) None of These - Mathematics

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Question

2 tan−1 {cosec (tan−1 x) − tan (cot1 x)} is equal to

Options

  • cot−1 x

  • cot−1`1/x`

  • tan−1 x

  • none of these

MCQ
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Solution

(c) tan−1 x
Let `tan^-1x=y`

So, `x=tany`

\[\therefore 2 \tan^{- 1} \left\{ cosec\left( \tan^{- 1} x \right) - \tan\left( co t^{- 1} x \right) \right\} = 2 \tan^{- 1} \left\{ cosec\left( \tan^{- 1} x \right) - \tan\left( \tan^{- 1} \frac{1}{x} \right) \right\} \]
\[ = 2 \tan^{- 1} \left\{ cosec\left( \tan^{- 1} x \right) - \frac{1}{x} \right\}\]
\[ = 2 \tan^{- 1} \left\{ cosec {y} - \frac{1}{\tan{y}} \right\}\]
\[ = 2 \tan^{- 1} \left\{ \frac{1 - \cos{y}}{\sin{y}} \right\}\]
\[ = 2 \tan^{- 1} \left\{ \frac{2 \sin^2 \frac{y}{2}}{\sin{y}} \right\} \]
\[ = 2 \tan^{- 1} \left\{ \frac{2 \sin^2 \frac{y}{2}}{2\sin\frac{y}{2}\cos\frac{y}{2}} \right\}\]
\[ = 2 \tan^{- 1} \left\{ \tan\frac{y}{2} \right\}\]
\[ = y\]
\[ = \tan^{- 1} x\]

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.16 [Page 120]

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RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 3 | Page 120

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