English

Evaluate the Following: `Tan(Cos^-1 8/17)` - Mathematics

Advertisements
Advertisements

Question

Evaluate the following:

`tan(cos^-1  8/17)`

Advertisements

Solution

`tan(cos^-1  8/17)=tan{tan^-1  (sqrt(1-(8/17)^2))/(8/17)}`    `[thereforecos^-1x=tan^-1  ((sqrt(1-x^2))/x)]`

`=tan(tan^-1  (15/17)/(8/17))`

`=15/8`

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.08 [Page 54]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.08 | Q 1.7 | Page 54

RELATED QUESTIONS

Write the value of `tan(2tan^(-1)(1/5))`


Solve the equation for x:sin1x+sin1(1x)=cos1x


If (tan1x)2 + (cot−1x)2 = 5π2/8, then find x.


`sin^-1(sin12)`


Evaluate the following:

`tan^-1(tan1)`


Evaluate the following:

`cot^-1{cot  ((21pi)/4)}`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)+1)/x},x !=0`


Write the following in the simplest form:

`tan^-1(x/(a+sqrt(a^2-x^2))),-a<x<a`


Evaluate:

`sec{cot^-1(-5/12)}`


Evaluate:

`tan{cos^-1(-7/25)}`


Evaluate:

`cos(tan^-1  3/4)`


If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.


If `(sin^-1x)^2+(cos^-1x)^2=(17pi^2)/36,`  Find x


`tan^-1x+2cot^-1x=(2x)/3`


Prove the following result:

`tan^-1  1/4+tan^-1  2/9=sin^-1  1/sqrt5`


Find the value of `tan^-1  (x/y)-tan^-1((x-y)/(x+y))`


Solve the following equation for x:

`tan^-1(2+x)+tan^-1(2-x)=tan^-1  2/3, where  x< -sqrt3 or, x>sqrt3`


`(9pi)/8-9/4sin^-1  1/3=9/4sin^-1  (2sqrt2)/3`


`2tan^-1  1/5+tan^-1  1/8=tan^-1  4/7`


Prove that

`sin{tan^-1  (1-x^2)/(2x)+cos^-1  (1-x^2)/(2x)}=1`


Solve the following equation for x:

`3sin^-1  (2x)/(1+x^2)-4cos^-1  (1-x^2)/(1+x^2)+2tan^-1  (2x)/(1-x^2)=pi/3`


Prove that `2tan^-1(sqrt((a-b)/(a+b))tan  theta/2)=cos^-1((a costheta+b)/(a+b costheta))`


For any a, b, x, y > 0, prove that:

`2/3tan^-1((3ab^2-a^3)/(b^3-3a^2b))+2/3tan^-1((3xy^2-x^3)/(y^3-3x^2y))=tan^-1  (2alphabeta)/(alpha^2-beta^2)`

`where  alpha =-ax+by, beta=bx+ay`


Write the difference between maximum and minimum values of  sin−1 x for x ∈ [− 1, 1].


If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2,`  then write the value of x + y + z.


If x > 1, then write the value of sin−1 `((2x)/(1+x^2))` in terms of tan−1 x.


What is the value of cos−1 `(cos  (2x)/3)+sin^-1(sin  (2x)/3)?`


Write the range of tan−1 x.


Write the value of cos\[\left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right)\]


Write the value of cos−1 \[\left( \cos\frac{5\pi}{4} \right)\]


Write the value of \[\sin^{- 1} \left( \frac{1}{3} \right) - \cos^{- 1} \left( - \frac{1}{3} \right)\]


Write the value of \[\tan^{- 1} \left\{ 2\sin\left( 2 \cos^{- 1} \frac{\sqrt{3}}{2} \right) \right\}\]


Write the value of \[\cos^{- 1} \left( \cos\frac{14\pi}{3} \right)\]


Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) = 


The value of \[\cos^{- 1} \left( \cos\frac{5\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{5\pi}{3} \right)\] is

 


If θ = sin−1 {sin (−600°)}, then one of the possible values of θ is

 


It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\]   (−7), then the value of x is

 


Prove that : \[\cot^{- 1} \frac{\sqrt{1 + \sin x} + \sqrt{1 - \sin x}}{\sqrt{1 + \sin x} - \sqrt{1 - \sin x}} = \frac{x}{2}, 0 < x < \frac{\pi}{2}\] .


If 2 tan−1 (cos θ) = tan−1 (2 cosec θ), (θ ≠ 0), then find the value of θ.


If \[\tan^{- 1} \left( \frac{1}{1 + 1 . 2} \right) + \tan^{- 1} \left( \frac{1}{1 + 2 . 3} \right) + . . . + \tan^{- 1} \left( \frac{1}{1 + n . \left( n + 1 \right)} \right) = \tan^{- 1} \theta\] , then find the value of θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×