Advertisements
Advertisements
प्रश्न
Evaluate the following:
`tan(cos^-1 8/17)`
Advertisements
उत्तर
`tan(cos^-1 8/17)=tan{tan^-1 (sqrt(1-(8/17)^2))/(8/17)}` `[thereforecos^-1x=tan^-1 ((sqrt(1-x^2))/x)]`
`=tan(tan^-1 (15/17)/(8/17))`
`=15/8`
APPEARS IN
संबंधित प्रश्न
If tan-1x+tan-1y=π/4,xy<1, then write the value of x+y+xy.
Find the domain of `f(x)=cos^-1x+cosx.`
Find the principal values of the following:
`cos^-1(tan (3pi)/4)`
`sin^-1(sin2)`
Evaluate the following:
`cos^-1(cos5)`
Evaluate the following:
`tan^-1(tan2)`
Evaluate the following:
`cosec^-1(cosec (3pi)/4)`
Evaluate the following:
`cosec^-1{cosec (-(9pi)/4)}`
Write the following in the simplest form:
`tan^-1{sqrt(1+x^2)-x},x in R`
Write the following in the simplest form:
`tan^-1{(sqrt(1+x^2)+1)/x},x !=0`
Write the following in the simplest form:
`tan^-1(x/(a+sqrt(a^2-x^2))),-a<x<a`
Evaluate the following:
`sin(cos^-1 5/13)`
Evaluate the following:
`sin(sec^-1 17/8)`
Evaluate:
`cos{sin^-1(-7/25)}`
`tan^-1x+2cot^-1x=(2x)/3`
Solve the following equation for x:
tan−1(x + 2) + tan−1(x − 2) = tan−1 `(8/79)`, x > 0
If `cos^-1 x/2+cos^-1 y/3=alpha,` then prove that `9x^2-12xy cosa+4y^2=36sin^2a.`
Evaluate the following:
`sin(1/2cos^-1 4/5)`
`tan^-1 1/7+2tan^-1 1/3=pi/4`
`2tan^-1 1/5+tan^-1 1/8=tan^-1 4/7`
Find the value of the following:
`cos(sec^-1x+\text(cosec)^-1x),` | x | ≥ 1
Write the value of sin−1
\[\left( \sin( -{600}°) \right)\].
Write the value of sin−1 (sin 1550°).
Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]
Write the value of cos−1 (cos 6).
Write the principal value of `tan^-1sqrt3+cot^-1sqrt3`
Find the value of \[\cos^{- 1} \left( \cos\frac{13\pi}{6} \right)\]
Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]
If \[\tan^{- 1} \left( \frac{\sqrt{1 + x^2} - \sqrt{1 - x^2}}{\sqrt{1 + x^2} + \sqrt{1 - x^2}} \right)\] = α, then x2 =
The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]
Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) =
\[\tan^{- 1} \frac{1}{11} + \tan^{- 1} \frac{2}{11}\] is equal to
If \[3\sin^{- 1} \left( \frac{2x}{1 + x^2} \right) - 4 \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) + 2 \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) = \frac{\pi}{3}\] is equal to
If 4 cos−1 x + sin−1 x = π, then the value of x is
It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\] (−7), then the value of x is
\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) =\]
If x > 1, then \[2 \tan^{- 1} x + \sin^{- 1} \left( \frac{2x}{1 + x^2} \right)\] is equal to
Find the real solutions of the equation
`tan^-1 sqrt(x(x + 1)) + sin^-1 sqrt(x^2 + x + 1) = pi/2`
The period of the function f(x) = tan3x is ____________.
