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Solve the Following Equation For X: Tan−1(X −1) + Tan−1x Tan−1(X + 1) = Tan−13x - Mathematics

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प्रश्न

Solve the following equation for x:

tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x

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उत्तर

We know

`tan^-1x+tan^-1y=tan^-1((x+y)/(1-zy))and tan^-1x-tan^-1y=tan^-1((x-y)/(1+xy))`

∴ tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x

⇒ `tan^-1{(x+1+x-1)/(1-(x+1)xx(x+1))}=tan^-1 3x-tan^-1x`

⇒ `tan^-1((2x)/(2-x^2))(=tan^-1((3x-x)/(1+3x^2))`

⇒ `(2x)/(2-x^2)=(2x)/(1+3x^2)`

⇒ `2-x^2=1+3x^2`

⇒ 4x2 - 1 = 0

⇒ `x^2=1/4`

⇒ `x=+-1/2`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.11 [पृष्ठ ८२]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.11 | Q 3.03 | पृष्ठ ८२

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