मराठी

Write the Value of Sec − 1 ( 1 2 ) - Mathematics

Advertisements
Advertisements

प्रश्न

Write the value of \[\sec^{- 1} \left( \frac{1}{2} \right)\]

Advertisements

उत्तर

The value of  `sec^-1(1/2)`  is undefined as it is outside the range i.e., R – (–1, 1) .

 
shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११८]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 47 | पृष्ठ ११८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

 

Prove that :

`2 tan^-1 (sqrt((a-b)/(a+b))tan(x/2))=cos^-1 ((a cos x+b)/(a+b cosx))`

 

Solve the following for x :

`tan^(-1)((x-2)/(x-3))+tan^(-1)((x+2)/(x+3))=pi/4,|x|<1`


 

Show that:

`2 sin^-1 (3/5)-tan^-1 (17/31)=pi/4`

 

 

If a line makes angles 90° and 60° respectively with the positive directions of x and y axes, find the angle which it makes with the positive direction of z-axis.


Find the domain of definition of `f(x)=cos^-1(x^2-4)`


`sin^-1(sin12)`


Evaluate the following:

`cos^-1(cos5)`


Evaluate the following:

`tan^-1(tan12)`


Evaluate the following:

`sec^-1(sec  pi/3)`


Write the following in the simplest form:

`sin^-1{(sqrt(1+x)+sqrt(1-x))/2},0<x<1`


Prove the following result

`tan(cos^-1  4/5+tan^-1  2/3)=17/6`


Solve: `cos(sin^-1x)=1/6`


Evaluate:

`cos(sec^-1x+\text(cosec)^-1x)`,|x|≥1


`sin(sin^-1  1/5+cos^-1x)=1`


Prove the following result:

`tan^-1  1/7+tan^-1  1/13=tan^-1  2/9`


Solve the following equation for x:

`tan^-1((1-x)/(1+x))-1/2 tan^-1x` = 0, where x > 0


`sin^-1  5/13+cos^-1  3/5=tan^-1  63/16`


Prove that: `cos^-1  4/5+cos^-1  12/13=cos^-1  33/65`


Evaluate the following:

`tan{2tan^-1  1/5-pi/4}`


Prove that:

`2sin^-1  3/5=tan^-1  24/7`


`2sin^-1  3/5-tan^-1  17/31=pi/4`


`2tan^-1  1/5+tan^-1  1/8=tan^-1  4/7`


If x < 0, then write the value of cos−1 `((1-x^2)/(1+x^2))` in terms of tan−1 x.


Write the value of sin (cot−1 x).


Evaluate sin

\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]


Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]


Write the value of cos \[\left( 2 \sin^{- 1} \frac{1}{2} \right)\]


If x < 0, y < 0 such that xy = 1, then write the value of tan1 x + tan−1 y.


Write the principal value of \[\cos^{- 1} \left( \cos\frac{2\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{2\pi}{3} \right)\]


Find the value of \[\cos^{- 1} \left( \cos\frac{13\pi}{6} \right)\]


\[\text{ If } u = \cot^{- 1} \sqrt{\tan \theta} - \tan^{- 1} \sqrt{\tan \theta}\text{ then }, \tan\left( \frac{\pi}{4} - \frac{u}{2} \right) =\]


If tan−1 3 + tan−1 x = tan−1 8, then x =


The value of \[\cos^{- 1} \left( \cos\frac{5\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{5\pi}{3} \right)\] is

 


It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\]   (−7), then the value of x is

 


The domain of  \[\cos^{- 1} \left( x^2 - 4 \right)\] is

 


If 2 tan−1 (cos θ) = tan−1 (2 cosec θ), (θ ≠ 0), then find the value of θ.


Find the value of `sin^-1(cos((33π)/5))`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×