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Evaluate the Following: `Sec^-1{Sec (-(7pi)/3)}` - Mathematics

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प्रश्न

Evaluate the following:

`sec^-1{sec  (-(7pi)/3)}`

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उत्तर

We know that

sec-1 (sec θ) = θ,    [0, π/2) ∪ (π/2, π]

 We have 

`sec^-1{sec  (-(7pi)/3)}=sec^-1{sec((7pi)/3)}`

`=sec^-1[sec(2pi+pi/3)]`

`=sec^-1[sec(pi/3)]`

`=pi/3`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.07 [पृष्ठ ४२]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.07 | Q 4.6 | पृष्ठ ४२

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