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`2tan^-1(1/2)+Tan^-1(1/7)=Tan^-1(31/17)` - Mathematics

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प्रश्न

`2tan^-1(1/2)+tan^-1(1/7)=tan^-1(31/17)`

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उत्तर

LHS = `2tan^-1(1/2)+tan^-1(1/7)`

`=tan^-1{(2xx1/2)/(1-(1/2)^2)}+tan^-1  1/7`     `[because2tan^-1x=tan^-1{(2x)/(1-x^2)}]`

`=tan^-1{1/(3/4)}+tan^-1  1/7`

`=tan^-1  4/3+tan^-1  1/7`

`=tan^-1((4/3+1/7)/(1-4/3xx1/7))`       `[because tan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))]`

`=tan^-1((31/21)/(17/21))`

`=tan^-1  31/17=`RHS

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.14 [पृष्ठ ११५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.14 | Q 2.09 | पृष्ठ ११५

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