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Find the real solutions of the equation tan-1x(x+1)+sin-1x2+x+1=π2 - Mathematics

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प्रश्न

Find the real solutions of the equation
`tan^-1 sqrt(x(x + 1)) + sin^-1 sqrt(x^2 + x + 1) = pi/2`

बेरीज
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उत्तर

We have `tan^-1 sqrt(x(x + 1)) + sin^-1 sqrt(x^2 + x + 1) = pi/2`

⇒ `tan^-1 sqrt(x(x +1)) = pi/2 - sin^-1 sqrt(x^2 + x + 1)`

= `cos^-1 sqrt(x^2 + x + 1)`

= `tan^-1  sqrt(-x^2 - x)/sqrt(x^2 +x + 1)`  ....(From the figure)

⇒ `sqrt(x(x + 1)) = sqrt(-x^2 - x)/sqrt(x^2 + x + 1)`

⇒ `x^2 + x` = 0

⇒ x = 0, –1

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पाठ 2: Inverse Trigonometric Functions - Exercise [पृष्ठ ३६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
पाठ 2 Inverse Trigonometric Functions
Exercise | Q 7 | पृष्ठ ३६

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