मराठी

The Value of Tan ( Cos − 1 3 5 + Tan − 1 1 4 ) (A) 19 8 (B) 8 19 (C) 19 12 (D) 3 4 - Mathematics

Advertisements
Advertisements

प्रश्न

The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]

 

पर्याय

  • `19/8`

  • `8/19`

  • `19/12`

  • `3/4`

MCQ
Advertisements

उत्तर

\[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right) = \tan\left( \tan^{- 1} \frac{\sqrt{1 - \frac{9}{25}}}{\frac{3}{5}} + \tan^{- 1} \frac{1}{4} \right)\]
\[ = \tan\left( \tan^{- 1} \frac{\frac{4}{5}}{\frac{3}{5}} + \tan^{- 1} \frac{1}{4} \right)\]
\[ = \tan\left( \tan^{- 1} \frac{4}{3} + \tan^{- 1} \frac{1}{4} \right)\]
\[ = \tan\left( \tan^{- 1} \frac{\frac{4}{3} + \frac{1}{4}}{1 - \frac{1}{3}} \right)\]
\[ = \frac{\frac{16 + 3}{12}}{\frac{2}{3}}\]
\[ = \frac{19}{8}\]

Hence, the correct answer is option (a).

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.16 [पृष्ठ १२२]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 35 | पृष्ठ १२२

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

If `cos^-1( x/a) +cos^-1 (y/b)=alpha` , prove that `x^2/a^2-2(xy)/(ab) cos alpha +y^2/b^2=sin^2alpha`


Solve for x:

`2tan^(-1)(cosx)=tan^(-1)(2"cosec" x)`


Solve the following for x:

`sin^(-1)(1-x)-2sin^-1 x=pi/2`


If sin [cot−1 (x+1)] = cos(tan1x), then find x.


​Find the principal values of the following:

`cos^-1(tan  (3pi)/4)`


Evaluate the following:

`tan^-1(tan12)`


Evaluate the following:

`cot^-1(cot  pi/3)`


Evaluate the following:

`cot^-1{cot (-(8pi)/3)}`


Write the following in the simplest form:

`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`


Evaluate the following:

`sin(tan^-1  24/7)`


Evaluate the following:

`sin(sec^-1  17/8)`


Evaluate the following:

`cosec(cos^-1  3/5)`


Evaluate the following:

`tan(cos^-1  8/17)`


Evaluate the following:

`cos(tan^-1  24/7)`


Evaluate:

`cos{sin^-1(-7/25)}`


If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.


Solve the following equation for x:

`tan^-1((1-x)/(1+x))-1/2 tan^-1x` = 0, where x > 0


`(9pi)/8-9/4sin^-1  1/3=9/4sin^-1  (2sqrt2)/3`


Evaluate the following:

`tan{2tan^-1  1/5-pi/4}`


Write the value of sin−1 \[\left( \cos\frac{\pi}{9} \right)\]


Write the value of \[\tan^{- 1} \frac{a}{b} - \tan^{- 1} \left( \frac{a - b}{a + b} \right)\]


Evaluate: \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]


Write the principal value of `sin^-1(-1/2)`


Write the value of \[\tan^{- 1} \left\{ 2\sin\left( 2 \cos^{- 1} \frac{\sqrt{3}}{2} \right) \right\}\]


If \[\cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = 0\], find the value of x.

 

If  \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]


sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\]  is equal to

 

 

The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


\[\tan^{- 1} \frac{1}{11} + \tan^{- 1} \frac{2}{11}\]  is equal to

 

 


The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is 

 


The domain of  \[\cos^{- 1} \left( x^2 - 4 \right)\] is

 


If x = a (2θ – sin 2θ) and y = a (1 – cos 2θ), find \[\frac{dy}{dx}\] When  \[\theta = \frac{\pi}{3}\] .


If \[\tan^{- 1} \left( \frac{1}{1 + 1 . 2} \right) + \tan^{- 1} \left( \frac{1}{1 + 2 . 3} \right) + . . . + \tan^{- 1} \left( \frac{1}{1 + n . \left( n + 1 \right)} \right) = \tan^{- 1} \theta\] , then find the value of θ.


Write the value of \[\cos^{- 1} \left( - \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\] .


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×