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The Value of Tan ( Cos − 1 3 5 + Tan − 1 1 4 ) (A) 19 8 (B) 8 19 (C) 19 12 (D) 3 4 - Mathematics

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Question

The value of \[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right)\]

 

Options

  • `19/8`

  • `8/19`

  • `19/12`

  • `3/4`

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Solution

\[\tan\left( \cos^{- 1} \frac{3}{5} + \tan^{- 1} \frac{1}{4} \right) = \tan\left( \tan^{- 1} \frac{\sqrt{1 - \frac{9}{25}}}{\frac{3}{5}} + \tan^{- 1} \frac{1}{4} \right)\]
\[ = \tan\left( \tan^{- 1} \frac{\frac{4}{5}}{\frac{3}{5}} + \tan^{- 1} \frac{1}{4} \right)\]
\[ = \tan\left( \tan^{- 1} \frac{4}{3} + \tan^{- 1} \frac{1}{4} \right)\]
\[ = \tan\left( \tan^{- 1} \frac{\frac{4}{3} + \frac{1}{4}}{1 - \frac{1}{3}} \right)\]
\[ = \frac{\frac{16 + 3}{12}}{\frac{2}{3}}\]
\[ = \frac{19}{8}\]

Hence, the correct answer is option (a).

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.16 [Page 122]

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RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 35 | Page 122

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