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Evaluate the Following: `Cot^-1(Cot (19pi)/6)` - Mathematics

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Question

Evaluate the following:

`cot^-1(cot  (19pi)/6)`

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Solution

We know that

cot-1 (cot θ) = θ,   (0, π)

We have

`cot^-1(cot  (19pi)/6)=cot^-1[cot(pi+pi/6)]`

`=cot^-1(cot  pi/6)`

`=pi/6`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.07 [Page 43]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.07 | Q 6.4 | Page 43

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