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Prove the Following Result `Tan(Cos^-1 4/5+Tan^-1 2/3)=17/6` - Mathematics

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Question

Prove the following result

`tan(cos^-1  4/5+tan^-1  2/3)=17/6`

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Solution

LHS=`tan(cos^-1  4/5+tan^-1  2/3)=tan(tan^-1  sqrt(1-(4/5)^2)/(4/5)+tan^-1  2/3)`    `[thereforecos^-1x=tan^-1(sqrt(1-x^2)/x)]`

`=tan(tan^-1  3/4+tan^-1  2/3)`

`=tan[tan^-1((3/4+2/3)/(1-3/4xx2/3))]`      `[thereforetan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))]`

`=tan[tan^-1((17/12)/(6/12))`

`=tan[tan^-1  17/6]`

`=17/6=`RHS

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.08 [Page 54]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.08 | Q 2.1 | Page 54

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