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Question
`sin^-1(sin4)`
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Solution
`sin^-1(sin4) = y`
`y = [-pi/2, pi/2]`
sin (4) = sin (y) → y = 4 → x
sin (4 − π + π)
sin (π + (4 − π))
−sin (4 − π)
sin (−(4 − π))
sin (π − 4) = sin (y)
y = π − 4
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