Question

`sin^-1(sin4)`

Answer 1

`sin^-1(sin4) = y`

`y = [-pi/2, pi/2]`

sin (4) = sin (y) → y = 4 → x

sin  (4 − π + π)

sin (π + (4 − π))

−sin (4 − π)

sin (−(4 − π))

sin (π − 4) = sin (y)

y = π − 4