मराठी

Evaluate: `Cos{Sin^-1(-7/25)}` - Mathematics

Advertisements
Advertisements

प्रश्न

Evaluate:

`cos{sin^-1(-7/25)}`

Advertisements

उत्तर

`cos{sin^-1(-7/25)}=cos{-sin^-1(7/25)}`

`=cos{sin^-1(7/25)}`

`=cos{cos^-1sqrt(1-(7/25)^2)}`

`=cos{cos^-1  24/25}`

`=24/25`

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.09 [पृष्ठ ५८]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.09 | Q 1.1 | पृष्ठ ५८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Write the value of `tan(2tan^(-1)(1/5))`


​Find the principal values of the following:
`cos^-1(-sqrt3/2)`


`sin^-1(sin  (13pi)/7)`


Evaluate the following:

`cos^-1{cos  (5pi)/4}`


Evaluate the following:

`tan^-1(tan  (7pi)/6)`


Evaluate the following:

`sec^-1{sec  (-(7pi)/3)}`


Evaluate the following:

`cosec^-1(cosec  (11pi)/6)`


Evaluate the following:

`cosec^-1{cosec  (-(9pi)/4)}`


Write the following in the simplest form:

`sin{2tan^-1sqrt((1-x)/(1+x))}`


Evaluate the following:

`sec(sin^-1  12/13)`


Evaluate:

`sin(tan^-1x+tan^-1  1/x)` for x < 0


If `sin^-1x+sin^-1y=pi/3`  and  `cos^-1x-cos^-1y=pi/6`,  find the values of x and y.


Solve the following equation for x:

`tan^-1  2x+tan^-1  3x = npi+(3pi)/4`


Solve the following equation for x:

tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x


Sum the following series:

`tan^-1  1/3+tan^-1  2/9+tan^-1  4/33+...+tan^-1  (2^(n-1))/(1+2^(2n-1))`


`2sin^-1  3/5-tan^-1  17/31=pi/4`


If `sin^-1  (2a)/(1+a^2)-cos^-1  (1-b^2)/(1+b^2)=tan^-1  (2x)/(1-x^2)`, then prove that `x=(a-b)/(1+ab)`


Solve the following equation for x:

`cos^-1((x^2-1)/(x^2+1))+1/2tan^-1((2x)/(1-x^2))=(2x)/3`


Prove that `2tan^-1(sqrt((a-b)/(a+b))tan  theta/2)=cos^-1((a costheta+b)/(a+b costheta))`


Write the difference between maximum and minimum values of  sin−1 x for x ∈ [− 1, 1].


If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2,`  then write the value of x + y + z.


Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]


Show that \[\sin^{- 1} (2x\sqrt{1 - x^2}) = 2 \sin^{- 1} x\]


Evaluate: \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]


If \[\sin^{- 1} \left( \frac{1}{3} \right) + \cos^{- 1} x = \frac{\pi}{2},\] then find x.

 


What is the principal value of `sin^-1(-sqrt3/2)?`


Write the value of \[\tan\left( 2 \tan^{- 1} \frac{1}{5} \right)\]


Write the value of \[\cos^{- 1} \left( \cos\frac{14\pi}{3} \right)\]


Write the value of \[\cos\left( \sin^{- 1} x + \cos^{- 1} x \right), \left| x \right| \leq 1\]


Wnte the value of\[\cos\left( \frac{\tan^{- 1} x + \cot^{- 1} x}{3} \right), \text{ when } x = - \frac{1}{\sqrt{3}}\]


The number of solutions of the equation \[\tan^{- 1} 2x + \tan^{- 1} 3x = \frac{\pi}{4}\] is

 


If α = \[\tan^{- 1} \left( \tan\frac{5\pi}{4} \right) \text{ and }\beta = \tan^{- 1} \left( - \tan\frac{2\pi}{3} \right)\] , then

 

The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is 

 


If \[\sin^{- 1} \left( \frac{2a}{1 - a^2} \right) + \cos^{- 1} \left( \frac{1 - a^2}{1 + a^2} \right) = \tan^{- 1} \left( \frac{2x}{1 - x^2} \right),\text{ where }a, x \in \left( 0, 1 \right)\] , then, the value of x is

 


If y = sin (sin x), prove that \[\frac{d^2 y}{d x^2} + \tan x \frac{dy}{dx} + y \cos^2 x = 0 .\]


Prove that : \[\cot^{- 1} \frac{\sqrt{1 + \sin x} + \sqrt{1 - \sin x}}{\sqrt{1 + \sin x} - \sqrt{1 - \sin x}} = \frac{x}{2}, 0 < x < \frac{\pi}{2}\] .


Write the value of \[\cos^{- 1} \left( - \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\] .


Find the domain of `sec^(-1)(3x-1)`.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×