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If `Cot(Cos^-1 3/5+Sin^-1x)=0`, Find the Values of X. - Mathematics

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प्रश्न

If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.

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उत्तर

`cot(cos^-1  3/5+sin^-1x)=0`

⇒ `cos^-1  3/5+sin^-1x=cot0`

⇒ `cos^-1  3/5sin^-1x=pi/2`

⇒ `cos^-1  3/5=pi/2-sin^-1x`

⇒ `cos^-1  3/5=cos^-1x`     `[becausecos^-1x=pi/2-sin^-1x]`

⇒ `x=3/5`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.10 [पृष्ठ ६६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.10 | Q 4 | पृष्ठ ६६

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