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Solve the Following Equation For X: `Tan^-1((X-2)/(X-1))+Tan^-1((X+2)/(X+1))=Pi/4` - Mathematics

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प्रश्न

Solve the following equation for x:

`tan^-1((x-2)/(x-1))+tan^-1((x+2)/(x+1))=pi/4`

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उत्तर

`tan^-1((x-2)/(x-1))+tan^-1((x+2)/(x+1))=pi/4`

`=>tan^-1((x-2)/(x-1))+tan^-1((x+2)/(x+1))=tan^-1 1`

`=>tan^-1((x-2)/(x-1))=tan^-1 1-tan^-1((x+2)/(x+1))`

`=>tan^-1((x-2)/(x-1))=tan^-1((1-(x+2)/(x+1))/(1+(x+2)/(x+1)))`

`=>tan^-1((x-2)/(x-1))=tan^-1((x+1-x-2)/(x+1+x+2))`

`=>tan^-1((x-2)/(x-1))=tan^-1((-1)/(2x+3))`

`=>(x-2)/(x-1)=(-1)/(2x+3)`

`=>2x^2+3x-4x-6=-x+1`

`=>2x^2=1+6`

`=>x^2=7`

`=>x=+-sqrt(7/2)`

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.14 [पृष्ठ ११६]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.14 | Q 8.6 | पृष्ठ ११६

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