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Prove the Following Result `Cos(Sin^-1 3/5+Cot^-1 3/2)=6/(5sqrt13)` - Mathematics

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Question

Prove the following result

`cos(sin^-1  3/5+cot^-1  3/2)=6/(5sqrt13)`

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Solution

LHS = `cos(sin^-1  3/5+cot^-1  3/2)`

`=cos(sin^-1  3/5+tan^-1  2/3)`

`=cos[cos^-1sqrt(1-(3/5)^2)+cos^-1  1/sqrt(1+(2/3)^2)]`

`=cos(cos^-1  4/5+cos^-1  3/sqrt13)`

`=cos{cos^-1[4/5xx3/sqrt13-sqrt(1-(4/5)^2)sqrt(1-(3/sqrt13)^2]}`

`=cos{cos^-1[12/(5sqrt13)-6/(5sqrt13)]}`

`=cos{cos^-1[6/(5sqrt13)]}`

`=6/(5sqrt13)=`RHS

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.08 [Page 54]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.08 | Q 2.2 | Page 54

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