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Tan − 1 1 11 + Tan − 1 2 11 is Equal to (A) 0 (B) 1/2 (C) − 1 (D) None of These - Mathematics

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Question

\[\tan^{- 1} \frac{1}{11} + \tan^{- 1} \frac{2}{11}\]  is equal to

 

 

Options

  • 0

  • 1/2

  • − 1

  • none of these

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Solution

(d) none of these

We know that 
\[\tan^{- 1} x + \tan^{- 1} y = \tan^{- 1} \left( \frac{x + y}{1 - xy} \right)\]
Now,
\[\tan^{- 1} \frac{1}{11} + \tan^{- 1} \frac{2}{11} = \tan^{- 1} \left( \frac{\frac{1}{11} + \frac{2}{11}}{1 - \frac{1}{11}\frac{2}{11}} \right)\]
\[ = \tan^{- 1} \left( \frac{\frac{3}{11}}{\frac{121 - 2}{121}} \right)\]
\[ = \tan^{- 1} \left( \frac{\frac{3}{11}}{\frac{119}{121}} \right)\]
\[ = \tan^{- 1} \left( \frac{33}{119} \right)\]
\[ = 0 . 27\]

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.16 [Page 121]

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RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 16 | Page 121

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