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Evaluate the Following: `Cos(Tan^-1 24/7)` - Mathematics

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Question

Evaluate the following:

`cos(tan^-1  24/7)`

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Solution

`cos(tan^-1  24/7)=cos[cos^-1  1/sqrt(1+(24/7)^2)]`    `[therefore tan^-1x=cos^-1  1/sqrt(1+z^2)]`

`=cos[cos^-1  1/sqrt(1+576/49)]`

`=cos[cos^-1  1/(25/7)]`

`=cos[cos^-1  7/25]`

`=7/25`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.08 [Page 54]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.08 | Q 1.9 | Page 54

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