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`Tan^-1 1/7+2tan^-1 1/3=Pi/4` - Mathematics

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Question

`tan^-1  1/7+2tan^-1  1/3=pi/4`

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Solution

LHS = `tan^-1  1/7+2tan^-1  1/3`

`=tan^-1  1/7+tan^-1{(2xx1/3)/(1-(1/3)^2)}`     `[because2tan^-1x=tan^-1{(2x)/(1-x^2)}]`

`=tan^-1  1/7+tan^-1{(2/3)/(8/9)}`

`=tan^-1  1/7+tan^-1  3/4`

`=tan^-1((1/7+3/4)/(1-1/7xx3/4))`       `[becausetan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))]`

`=tan^-1((25/28)/(25/28))`

`=tan^-1 1=pi/4=`RHS

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.14 [Page 115]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.14 | Q 2.04 | Page 115

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