English

Evaluate: `Cot(Sin^-1 3/4+Sec^-1 4/3)` - Mathematics

Advertisements
Advertisements

Question

Evaluate: 

`cot(sin^-1  3/4+sec^-1  4/3)`

Advertisements

Solution

`cot(sin^-1  3/4+sec^-1  4/3)`

`=cot(sin^-1  3/4 + cos^-1  3/4)`     `[thereforesec^-1x=cos^-1  1/x]`

`=cot(pi/2)`     `[thereforesin^-1x+cos^-1x=pi/2]`

= 0

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.10 [Page 66]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.10 | Q 1.1 | Page 66

RELATED QUESTIONS

Write the value of `tan(2tan^(-1)(1/5))`


Solve for x:

`2tan^(-1)(cosx)=tan^(-1)(2"cosec" x)`


If sin [cot−1 (x+1)] = cos(tan1x), then find x.


If (tan1x)2 + (cot−1x)2 = 5π2/8, then find x.


`sin^-1(sin  (17pi)/8)`


`sin^-1{(sin - (17pi)/8)}`


`sin^-1(sin12)`


Evaluate the following:

`sec^-1(sec  pi/3)`


Evaluate the following:

`cosec^-1(cosec  (3pi)/4)`


Evaluate the following:

`cosec^-1(cosec  (6pi)/5)`


Write the following in the simplest form:

`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`


Evaluate the following:

`sin(sin^-1  7/25)`

 


Prove the following result

`sin(cos^-1  3/5+sin^-1  5/13)=63/65`


Evaluate:

`cos(tan^-1  3/4)`


Evaluate:

`cos(sec^-1x+\text(cosec)^-1x)`,|x|≥1


If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.


Find the value of `tan^-1  (x/y)-tan^-1((x-y)/(x+y))`


Solve the following equation for x:

`tan^-1((1-x)/(1+x))-1/2 tan^-1x` = 0, where x > 0


If `sin^-1  (2a)/(1+a^2)+sin^-1  (2b)/(1+b^2)=2tan^-1x,` Prove that  `x=(a+b)/(1-ab).`


Prove that `2tan^-1(sqrt((a-b)/(a+b))tan  theta/2)=cos^-1((a costheta+b)/(a+b costheta))`


If `sin^-1x+sin^-1y+sin^-1z=(3pi)/2,`  then write the value of x + y + z.


Write the value of tan1x + tan−1 `(1/x)`for x > 0.


Write the value of sin (cot−1 x).


Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]


Write the principal value of \[\sin^{- 1} \left\{ \cos\left( \sin^{- 1} \frac{1}{2} \right) \right\}\]


If \[\cos\left( \tan^{- 1} x + \cot^{- 1} \sqrt{3} \right) = 0\] , find the value of x.

 

Find the value of \[2 \sec^{- 1} 2 + \sin^{- 1} \left( \frac{1}{2} \right)\]


The positive integral solution of the equation
\[\tan^{- 1} x + \cos^{- 1} \frac{y}{\sqrt{1 + y^2}} = \sin^{- 1} \frac{3}{\sqrt{10}}\text{ is }\]


\[\text{ If }\cos^{- 1} \frac{x}{3} + \cos^{- 1} \frac{y}{2} = \frac{\theta}{2}, \text{ then }4 x^2 - 12xy \cos\frac{\theta}{2} + 9 y^2 =\]


Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) = 


If 4 cos−1 x + sin−1 x = π, then the value of x is

 


\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) =\] 

 


If y = sin (sin x), prove that \[\frac{d^2 y}{d x^2} + \tan x \frac{dy}{dx} + y \cos^2 x = 0 .\]


If 2 tan−1 (cos θ) = tan−1 (2 cosec θ), (θ ≠ 0), then find the value of θ.


Find the value of x, if tan `[sec^(-1) (1/x) ] = sin ( tan^(-1) 2) , x > 0 `.


Find the simplified form of `cos^-1 (3/5 cosx + 4/5 sin x)`, where x ∈ `[(-3pi)/4, pi/4]`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×