English

Evaluate: `Sin{Cos^-1(-3/5)+Cot^-1(-5/12)}` - Mathematics

Advertisements
Advertisements

Question

Evaluate: `sin{cos^-1(-3/5)+cot^-1(-5/12)}`

Advertisements

Solution

`sin{cos^-1(-3/5)+cot^-1(-5/12)}=sin{pi-cos^-1(3/5)+pi-cot^-1(5/12)}`

`=sin{2pi-[cos^-1(3/5)+cot^-1(5/12)]}`

`=-sin{cos^-1(3/5)+cot^-1(5/12)}`

`=-sin{sin^-1[sqrt(1-(3/5)^2)]+sin^-1[(12/5)/sqrt(1+(12/5)^2)]}`

`=-sin(sin^-1  4/5+sin^-1  12/13)`

`=-sin{sin^-1[4/5xxsqrt(1-(12/13)^2)=12/13xxsqrt(1-(4/5)^2)]}`

`=-sin[sin^-1(20/65+36/65)]`

`=-sin[sin^-1(56/65)]`

`=-56/65`

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.09 [Page 59]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.09 | Q 3 | Page 59

RELATED QUESTIONS

Solve the equation for x:sin1x+sin1(1x)=cos1x


Solve the following for x :

`tan^(-1)((x-2)/(x-3))+tan^(-1)((x+2)/(x+3))=pi/4,|x|<1`


Find the domain of  `f(x) =2cos^-1 2x+sin^-1x.`


`sin^-1(sin  (7pi)/6)`


`sin^-1(sin4)`


`sin^-1(sin2)`


Evaluate the following:

`cos^-1(cos3)`


Evaluate the following:

`cos^-1(cos12)`


Evaluate the following:

`sec^-1(sec  (9pi)/5)`


Evaluate the following:

`sec^-1(sec  (13pi)/4)`


Evaluate the following:

`cosec^-1(cosec  (3pi)/4)`


Evaluate the following:

`cosec^-1(cosec  (6pi)/5)`


Evaluate the following:

`cot^-1(cot  (9pi)/4)`


Write the following in the simplest form:

`cot^-1  a/sqrt(x^2-a^2),|  x  | > a`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`


Write the following in the simplest form:

`sin^-1{(sqrt(1+x)+sqrt(1-x))/2},0<x<1`


Evaluate the following:

`sin(cos^-1  5/13)`


Evaluate the following:

`sec(sin^-1  12/13)`


Prove the following result-

`tan^-1  63/16 = sin^-1  5/13 + cos^-1  3/5`


If `cot(cos^-1  3/5+sin^-1x)=0`, find the values of x.


`4sin^-1x=pi-cos^-1x`


Solve the following:

`cos^-1x+sin^-1  x/2=π/6`


Prove that:

`2sin^-1  3/5=tan^-1  24/7`


If `sin^-1  (2a)/(1+a^2)+sin^-1  (2b)/(1+b^2)=2tan^-1x,` Prove that  `x=(a+b)/(1-ab).`


Solve the following equation for x:

`tan^-1((2x)/(1-x^2))+cot^-1((1-x^2)/(2x))=(2pi)/3,x>0`


Write the value of `sin^-1((-sqrt3)/2)+cos^-1((-1)/2)`


If x < 0, then write the value of cos−1 `((1-x^2)/(1+x^2))` in terms of tan−1 x.


Write the value of tan1 x + tan−1 `(1/x)`  for x < 0.


If \[\sin^{- 1} \left( \frac{1}{3} \right) + \cos^{- 1} x = \frac{\pi}{2},\] then find x.

 


Write the principal value of \[\cos^{- 1} \left( \cos680^\circ  \right)\]


The value of tan \[\left\{ \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right\}\] is

 


2 tan−1 {cosec (tan−1 x) − tan (cot1 x)} is equal to


If  \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]


sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\]  is equal to

 

 

The value of \[\sin^{- 1} \left( \cos\frac{33\pi}{5} \right)\] is 

 


It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\]   (−7), then the value of x is

 


If tan−1 (cot θ) = 2 θ, then θ =

 


If 2 tan−1 (cos θ) = tan−1 (2 cosec θ), (θ ≠ 0), then find the value of θ.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×