English

Cot ( π 4 − 2 Cot − 1 3 ) = (A) 7 (B) 6 (C) 5 (D) None of These - Mathematics

Advertisements
Advertisements

Question

\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) =\] 

 

Options

  • 7

  • 6

  • 5

  • none of these

MCQ
Advertisements

Solution

(a) 7

Let  \[2 \cot^{- 1} 3 = y\]
Then,
\[\cot\frac{y}{2} = 3\]
\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) = \cot\left( \frac{\pi}{4} - y \right)\]
\[ = \frac{\cot\frac{\pi}{4}\cot{y} + 1}{\cot{y} - \cot\frac{\pi}{4}}\]
\[ = \frac{\cot{y} + 1}{\cot{y} - 1} \]
\[ = \frac{\frac{\cot^2 \frac{y}{2} - 1}{2\cot\frac{y}{2}} + 1}{\frac{\cot^2 \frac{y}{2} - 1}{2\cot\frac{y}{2}} - 1}\]
\[ = \frac{\cot^2 \frac{y}{2} + 2\cot\frac{y}{2} - 1}{\cot^2 \frac{y}{2} - 2\cot\frac{y}{2} - 1}\]
\[ = \frac{9 + 6 - 1}{9 - 6 - 1}\]
\[ = 7\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.16 [Page 122]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 29 | Page 122

RELATED QUESTIONS

Find the domain of `f(x)=cos^-1x+cosx.`


​Find the principal values of the following:
`cos^-1(-sqrt3/2)`


`sin^-1{(sin - (17pi)/8)}`


Evaluate the following:

`tan^-1(tan  (6pi)/7)`


Evaluate the following:

`tan^-1(tan12)`


Evaluate the following:

`cot^-1{cot (-(8pi)/3)}`


Evaluate the following:

`sin(cos^-1  5/13)`


Prove the following result-

`tan^-1  63/16 = sin^-1  5/13 + cos^-1  3/5`


Evaluate:

`cos(tan^-1  3/4)`


Evaluate:

`sin(tan^-1x+tan^-1  1/x)` for x < 0


Evaluate:

`cot(tan^-1a+cot^-1a)`


`tan^-1x+2cot^-1x=(2x)/3`


Find the value of `tan^-1  (x/y)-tan^-1((x-y)/(x+y))`


Solve the following equation for x:

tan−1(x −1) + tan−1x tan−1(x + 1) = tan−13x


Evaluate: `cos(sin^-1  3/5+sin^-1  5/13)`


`sin^-1  63/65=sin^-1  5/13+cos^-1  3/5`


Evaluate the following:

`sin(1/2cos^-1  4/5)`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


`2sin^-1  3/5-tan^-1  17/31=pi/4`


`2tan^-1(1/2)+tan^-1(1/7)=tan^-1(31/17)`


Prove that

`tan^-1((1-x^2)/(2x))+cot^-1((1-x^2)/(2x))=pi/2`


Solve the following equation for x:

`tan^-1  1/4+2tan^-1  1/5+tan^-1  1/6+tan^-1  1/x=pi/4`


For any a, b, x, y > 0, prove that:

`2/3tan^-1((3ab^2-a^3)/(b^3-3a^2b))+2/3tan^-1((3xy^2-x^3)/(y^3-3x^2y))=tan^-1  (2alphabeta)/(alpha^2-beta^2)`

`where  alpha =-ax+by, beta=bx+ay`


Write the difference between maximum and minimum values of  sin−1 x for x ∈ [− 1, 1].


Write the value of tan1x + tan−1 `(1/x)`for x > 0.


What is the value of cos−1 `(cos  (2x)/3)+sin^-1(sin  (2x)/3)?`


Write the value of cos−1 (cos 1540°).


Evaluate sin

\[\left( \frac{1}{2} \cos^{- 1} \frac{4}{5} \right)\]


Write the principal value of \[\tan^{- 1} 1 + \cos^{- 1} \left( - \frac{1}{2} \right)\]


The positive integral solution of the equation
\[\tan^{- 1} x + \cos^{- 1} \frac{y}{\sqrt{1 + y^2}} = \sin^{- 1} \frac{3}{\sqrt{10}}\text{ is }\]


If α = \[\tan^{- 1} \left( \tan\frac{5\pi}{4} \right) \text{ and }\beta = \tan^{- 1} \left( - \tan\frac{2\pi}{3} \right)\] , then

 

The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


If x < 0, y < 0 such that xy = 1, then tan−1 x + tan−1 y equals

 


It \[\tan^{- 1} \frac{x + 1}{x - 1} + \tan^{- 1} \frac{x - 1}{x} = \tan^{- 1}\]   (−7), then the value of x is

 


Write the value of \[\cos^{- 1} \left( - \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\] .


Find the domain of `sec^(-1)(3x-1)`.


The value of sin `["cos"^-1 (7/25)]` is ____________.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×