Question

Evaluate the following:

`sec(sin^-1  12/13)`

Answer 1

`sec(sin^-1  12/13)=sec[cos^-1sqrt(1-(12/13)^3)]`    
`[thereforesin^-1x=cos^-1sqrt(1-x^2)]`

`=sec[cos^-1(sqrt(1-144/169))]`

`=sec[cos^-1(sqrt(25/169))]`

`=sec[cos^-1  5/13]`

`=sec[sec^-1  13/5]`

`==13/5`