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प्रश्न
Evaluate the following:
`sec(sin^-1 12/13)`
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उत्तर
`sec(sin^-1 12/13)=sec[cos^-1sqrt(1-(12/13)^3)]`
`[thereforesin^-1x=cos^-1sqrt(1-x^2)]`
`=sec[cos^-1(sqrt(1-144/169))]`
`=sec[cos^-1(sqrt(25/169))]`
`=sec[cos^-1 5/13]`
`=sec[sec^-1 13/5]`
`==13/5`
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