English

Write the Range of Tan−1 X. - Mathematics

Advertisements
Advertisements

Question

Write the range of tan−1 x.

Advertisements

Solution

The range of

\[\tan^{- 1} x\] is

\[\left( - \frac{\pi}{2}, \frac{\pi}{2} \right)\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.15 [Page 117]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 12 | Page 117

RELATED QUESTIONS

Find the value of the following: `tan(1/2)[sin^(-1)((2x)/(1+x^2))+cos^(-1)((1-y^2)/(1+y^2))],|x| <1,y>0 and xy <1`


 

Show that:

`2 sin^-1 (3/5)-tan^-1 (17/31)=pi/4`

 

 

If tan-1x+tan-1y=π/4,xy<1, then write the value of x+y+xy.


Find the domain of definition of `f(x)=cos^-1(x^2-4)`


`sin^-1(sin  (7pi)/6)`


`sin^-1(sin4)`


`sin^-1(sin12)`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`sec^-1(sec  pi/3)`


Evaluate the following:

`cot^-1(cot  (9pi)/4)`


Write the following in the simplest form:

`tan^-1(x/(a+sqrt(a^2-x^2))),-a<x<a`


Write the following in the simplest form:

`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`


Evaluate the following:

`cosec(cos^-1  3/5)`


Solve: `cos(sin^-1x)=1/6`


Evaluate:

`sec{cot^-1(-5/12)}`


Evaluate:

`cosec{cot^-1(-12/5)}`


Evaluate:

`cos(tan^-1  3/4)`


Evaluate:

`cot(tan^-1a+cot^-1a)`


`4sin^-1x=pi-cos^-1x`


Prove the following result:

`sin^-1  12/13+cos^-1  4/5+tan^-1  63/16=pi`


Solve the following equation for x:

`tan^-1  (x-2)/(x-1)+tan^-1  (x+2)/(x+1)=pi/4`


Evaluate: `cos(sin^-1  3/5+sin^-1  5/13)`


`sin^-1  5/13+cos^-1  3/5=tan^-1  63/16`


Evaluate the following:

`sin(1/2cos^-1  4/5)`


`4tan^-1  1/5-tan^-1  1/239=pi/4`


Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]


Write the value of \[\tan^{- 1} \frac{a}{b} - \tan^{- 1} \left( \frac{a - b}{a + b} \right)\]


Write the value of cos−1 \[\left( \cos\frac{5\pi}{4} \right)\]


If \[\tan^{- 1} (\sqrt{3}) + \cot^{- 1} x = \frac{\pi}{2},\] find x.


Find the value of \[\tan^{- 1} \left( \tan\frac{9\pi}{8} \right)\]


If  \[\cos^{- 1} \frac{x}{a} + \cos^{- 1} \frac{y}{b} = \alpha, then\frac{x^2}{a^2} - \frac{2xy}{ab}\cos \alpha + \frac{y^2}{b^2} = \]


If tan−1 3 + tan−1 x = tan−1 8, then x =


sin \[\left\{ 2 \cos^{- 1} \left( \frac{- 3}{5} \right) \right\}\]  is equal to

 


If 4 cos−1 x + sin−1 x = π, then the value of x is

 


\[\cot\left( \frac{\pi}{4} - 2 \cot^{- 1} 3 \right) =\] 

 


Find the real solutions of the equation
`tan^-1 sqrt(x(x + 1)) + sin^-1 sqrt(x^2 + x + 1) = pi/2`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×