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Write the Value of \[\Cos^{- 1} \Left( \Frac{1}{2} \Right) + 2 \Sin^{- 1} \Left( \Frac{1}{2} \Right)\]. - Mathematics

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Question

Write the value of

\[\cos^{- 1} \left( \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right)\].

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Solution

We have

\[\cos^{- 1} \frac{1}{2} + 2 \sin^{- 1} \frac{1}{2}\]
\[ = \cos^{- 1} \left( \cos\frac{\pi}{3} \right) + 2 \sin^{- 1} \left( \sin\frac{\pi}{6} \right)\]

`[because"The range of sine is" [-pi/2,pi/2];  pi/6 in[-pi/2,pi/2] "and the range of cosine is"  [0,pi] ;  pi/3 in  [0,pi]]`
\[ = \frac{\pi}{3} + 2\left( \frac{\pi}{6} \right)\]
\[ = \frac{\pi}{3} + \frac{\pi}{3}\]
\[ = \frac{2\pi}{3}\]

∴ \[\cos^{- 1} \left( \frac{1}{2} \right) + 2 \sin^{- 1} \left( \frac{1}{2} \right) = \frac{2\pi}{3}\]

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.15 [Page 117]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 11 | Page 117

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