Question

2 tan⁻¹ {cosec (tan⁻¹ x) − tan (cot⁻¹ x)} is equal to

पर्याय

• cot⁻¹ x

• cot⁻¹`1/x`

• tan⁻¹ x

• none of these

Answer 1

(c) tan⁻¹ x
Let `tan^-1x=y`

So, `x=tany`

\[\therefore 2 \tan^{- 1} \left\{ cosec\left( \tan^{- 1} x \right) - \tan\left( co t^{- 1} x \right) \right\} = 2 \tan^{- 1} \left\{ cosec\left( \tan^{- 1} x \right) - \tan\left( \tan^{- 1} \frac{1}{x} \right) \right\} \]
\[ = 2 \tan^{- 1} \left\{ cosec\left( \tan^{- 1} x \right) - \frac{1}{x} \right\}\]
\[ = 2 \tan^{- 1} \left\{ cosec {y} - \frac{1}{\tan{y}} \right\}\]
\[ = 2 \tan^{- 1} \left\{ \frac{1 - \cos{y}}{\sin{y}} \right\}\]
\[ = 2 \tan^{- 1} \left\{ \frac{2 \sin^2 \frac{y}{2}}{\sin{y}} \right\} \]
\[ = 2 \tan^{- 1} \left\{ \frac{2 \sin^2 \frac{y}{2}}{2\sin\frac{y}{2}\cos\frac{y}{2}} \right\}\]
\[ = 2 \tan^{- 1} \left\{ \tan\frac{y}{2} \right\}\]
\[ = y\]
\[ = \tan^{- 1} x\]