मराठी

Write the Value of Tan − 1 { 2 Sin ( 2 Cos − 1 √ 3 2 ) } - Mathematics

Advertisements
Advertisements

प्रश्न

Write the value of \[\tan^{- 1} \left\{ 2\sin\left( 2 \cos^{- 1} \frac{\sqrt{3}}{2} \right) \right\}\]

Advertisements

उत्तर

\[\tan^{- 1} \left\{ 2\sin\left( 2 \cos^{- 1} \frac{\sqrt{3}}{2} \right) \right\} = \tan^{- 1} \left\{ 2\sin\left[ \cos^{- 1} 2 \left( \frac{\sqrt{3}}{2} \right)^2 - 1 \right] \right\}\]
\[ = \tan^{- 1} \left[ 2\sin\left( \cos^{- 1} \frac{1}{2} \right) \right]\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 4: Inverse Trigonometric Functions - Exercise 4.15 [पृष्ठ ११८]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 43 | पृष्ठ ११८

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

If `(sin^-1x)^2 + (sin^-1y)^2+(sin^-1z)^2=3/4pi^2,`  find the value of x2 + y2 + z2 


`sin^-1(sin  (5pi)/6)`


`sin^-1(sin3)`


`sin^-1(sin4)`


`sin^-1(sin2)`


Evaluate the following:

`tan^-1(tan  (9pi)/4)`


Evaluate the following:

`sec^-1(sec  (5pi)/4)`


Evaluate the following:

`sec^-1(sec  (13pi)/4)`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`


Write the following in the simplest form:

`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`


Evaluate the following:

`sin(tan^-1  24/7)`


Evaluate:

`cosec{cot^-1(-12/5)}`


Evaluate:

`cos(tan^-1  3/4)`


Evaluate:

`sin(tan^-1x+tan^-1  1/x)` for x < 0


Prove the following result:

`sin^-1  12/13+cos^-1  4/5+tan^-1  63/16=pi`


Solve the equation `cos^-1  a/x-cos^-1  b/x=cos^-1  1/b-cos^-1  1/a`


Solve `cos^-1sqrt3x+cos^-1x=pi/2`


Evaluate the following:

`tan  1/2(cos^-1  sqrt5/3)`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


`2tan^-1  3/4-tan^-1  17/31=pi/4`


Solve the following equation for x:

`3sin^-1  (2x)/(1+x^2)-4cos^-1  (1-x^2)/(1+x^2)+2tan^-1  (2x)/(1-x^2)=pi/3`


Solve the following equation for x:

`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`


Prove that:

`tan^-1  (2ab)/(a^2-b^2)+tan^-1  (2xy)/(x^2-y^2)=tan^-1  (2alphabeta)/(alpha^2-beta^2),`   where `alpha=ax-by  and  beta=ay+bx.`


Write the value of tan1 x + tan−1 `(1/x)`  for x < 0.


Write the value of cos\[\left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right)\]


Show that \[\sin^{- 1} (2x\sqrt{1 - x^2}) = 2 \sin^{- 1} x\]


If \[\sin^{- 1} \left( \frac{1}{3} \right) + \cos^{- 1} x = \frac{\pi}{2},\] then find x.

 


Write the principal value of \[\cos^{- 1} \left( \cos680^\circ  \right)\]


If sin−1 − cos−1 x = `pi/6` , then x = 


Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) = 


In a ∆ ABC, if C is a right angle, then
\[\tan^{- 1} \left( \frac{a}{b + c} \right) + \tan^{- 1} \left( \frac{b}{c + a} \right) =\]

 

 


The value of  \[\sin\left( 2\left( \tan^{- 1} 0 . 75 \right) \right)\] is equal to

 


If > 1, then \[2 \tan^{- 1} x + \sin^{- 1} \left( \frac{2x}{1 + x^2} \right)\] is equal to

 


The domain of  \[\cos^{- 1} \left( x^2 - 4 \right)\] is

 


If x = a (2θ – sin 2θ) and y = a (1 – cos 2θ), find \[\frac{dy}{dx}\] When  \[\theta = \frac{\pi}{3}\] .


If 2 tan−1 (cos θ) = tan−1 (2 cosec θ), (θ ≠ 0), then find the value of θ.


Find the simplified form of `cos^-1 (3/5 cosx + 4/5 sin x)`, where x ∈ `[(-3pi)/4, pi/4]`


Solve for x : {xcos(cot-1 x) + sin(cot-1 x)}= `51/50`


The value of sin `["cos"^-1 (7/25)]` is ____________.


The value of tan `("cos"^-1  4/5 + "tan"^-1  2/3) =`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×