मराठी

Let F (X) = E Cos − 1 { Sin ( X + π 3 } . Then, F (8π/9) = (A) E5π/18 (B) E13π/18 (C) E−2π/18 (D) None of These - Mathematics

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प्रश्न

Let f (x) = `e^(cos^-1){sin(x+pi/3}.`
Then, f (8π/9) = 

पर्याय

  • e5π/18

  •  e13π/18

  • e−2π/18

  • none of these

MCQ
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उत्तर

(b) e13π/18

Given: \[f\left( x \right) = e^{\cos^{- 1}} \left\{ \sin\left( x + \frac{\pi}{3} \right) \right\}\]
Then,

\[f\left( \frac{8\pi}{9} \right) = e^{\cos^{- 1}} \left\{ \sin\left( \frac{8\pi}{9} + \frac{\pi}{3} \right) \right\} \]
\[ = e^{\cos^{- 1}} \left\{ \sin\left( \frac{11\pi}{9} \right) \right\} \]
\[ = e^{\cos^{- 1}} \left\{ \cos\left( \frac{\pi}{2} + \frac{13\pi}{18} \right) \right\} \left[ \because \cos\left( \frac{\pi}{2} + \theta \right) = \sin\theta \right]\]
\[ = e^{\cos^{- 1}} \left\{ \cos\left( \frac{13\pi}{18} \right) \right\} \]
\[ = e^\frac{13\pi}{18}\]

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पाठ 4: Inverse Trigonometric Functions - Exercise 4.16 [पृष्ठ १२१]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 4 Inverse Trigonometric Functions
Exercise 4.16 | Q 15 | पृष्ठ १२१

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