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Evaluate the Following: `Sec^-1(Sec (13pi)/4)` - Mathematics

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Question

Evaluate the following:

`sec^-1(sec  (13pi)/4)`

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Solution

We know that

sec-1 (sec θ) = θ,    [0, π/2) ∪ (π/2, π]

 We have 

`sec^-1(sec  (13pi)/4)=sec^-1[sec(4pi-(3pi)/4)]`

`=sec^-1[sec((3pi)/4)]`

`=(3pi)/4`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.07 [Page 42]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.07 | Q 4.7 | Page 42

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