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Write the Value of Sin - Mathematics

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Question

Write the value of sin \[\left\{ \frac{\pi}{3} - \sin^{- 1} \left( - \frac{1}{2} \right) \right\}\]

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Solution

We have
\[\sin\left\{ \frac{\pi}{3} - \sin^{- 1} \left( - \frac{1}{2} \right) \right\} = \sin\left\{ \frac{\pi}{3} - \left( - \frac{\pi}{6} \right) \right\}\]
\[ = \sin\left\{ \frac{\pi}{3} + \frac{\pi}{6} \right\}\]
\[ = \sin\frac{\pi}{2}\]
\[ = 1\]
∴ \[\sin\left\{ \frac{\pi}{3} - \sin^{- 1} \left( - \frac{1}{2} \right) \right\} = 1\]

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.15 [Page 117]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 26 | Page 117

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