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Solve the Following Equation For X: `Tan^-1(2+X)+Tan^-1(2-x)=Tan^-1 2/3, Where X< -sqrt3 Or, X>Sqrt3` - Mathematics

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Question

Solve the following equation for x:

`tan^-1(2+x)+tan^-1(2-x)=tan^-1  2/3, where  x< -sqrt3 or, x>sqrt3`

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Solution

We know

`tan^-1x+tan^-1y=tan^-1((x+y)/(1-xy))`

∴ `tan^-1(2+x)+tan^-1(2-x)=tan^-1  2/3`

⇒ `tan^-1((2+x+2-x)/(1-(2+x)xx(2-x)))=tan^-1  2/3`

⇒ `4/(1-4+x^2)=2/3`

⇒ `-6+2x^2=12`

⇒ `2x^2=18`

⇒ `x^2=9`

⇒ `x=+-3`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.11 [Page 82]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.11 | Q 3.09 | Page 82

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