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If Cos ( Sin − 1 2 5 + Cos − 1 X ) = 0 , Find the Value of X. - Mathematics

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Question

If \[\cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = 0\], find the value of x.

 
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Solution

\[\cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = 0\]
\[ \Rightarrow \cos\left( \sin^{- 1} \frac{2}{5} + \cos^{- 1} x \right) = \cos\left( \frac{\pi}{2} \right)\]
\[ \Rightarrow \sin^{- 1} \frac{2}{5} + \cos^{- 1} x = \frac{\pi}{2}\]
\[ \therefore x = \frac{2}{5} \left[ \because \sin^{- 1} y + \cos^{- 1} y = \frac{\pi}{2} \right]\]
\[\]

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.15 [Page 119]

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RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 58 | Page 119

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