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Evaluate: `Cot{Sec^-1(-13/5)}` - Mathematics

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Question

Evaluate:

`cot{sec^-1(-13/5)}`

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Solution

`cot{sec^-1(-13/5)}=cot{sec^-1(pi-13/5)}`

`=-cot{sec^-1(13/5)}`

`=-cot{tan^-1(sqrt(1-(5/13)^3)/(5/13))}`

`=-cot{tan^-1(12/5)}`

`=-cot{cot^-1(5/12)}`

`=-5/12`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.09 [Page 58]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.09 | Q 1.3 | Page 58

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