Advertisements
Advertisements
Question
Evaluate:
`sec{cot^-1(-5/12)}`
Advertisements
Solution
`sec{cot^-1(-5/12)}=sec{pi-cot^-1(5/12)}`
`=-sec{cot^-1(5/12)}`
`=-sec{cos^-1[1/(1+(12/5)^2)]}`
`=-sec{cos^-1(5/13)}`
`=-sec{sec^-1
(13/5)}`
`=-13/5`
APPEARS IN
RELATED QUESTIONS
Prove that :
`2 tan^-1 (sqrt((a-b)/(a+b))tan(x/2))=cos^-1 ((a cos x+b)/(a+b cosx))`
`sin^-1(sin pi/6)`
`sin^-1(sin (13pi)/7)`
`sin^-1(sin3)`
`sin^-1(sin4)`
Evaluate the following:
`tan^-1(tan (6pi)/7)`
Evaluate the following:
`tan^-1(tan (9pi)/4)`
Evaluate the following:
`tan^-1(tan2)`
Evaluate the following:
`cosec^-1(cosec (3pi)/4)`
Evaluate the following:
`cosec^-1{cosec (-(9pi)/4)}`
Evaluate the following:
`cot^-1(cot (4pi)/3)`
Write the following in the simplest form:
`tan^-1{sqrt(1+x^2)-x},x in R`
Evaluate the following:
`sin(sin^-1 7/25)`
Evaluate the following:
`sin(tan^-1 24/7)`
Evaluate the following:
`sec(sin^-1 12/13)`
Evaluate:
`cos{sin^-1(-7/25)}`
Evaluate:
`tan{cos^-1(-7/25)}`
`sin(sin^-1 1/5+cos^-1x)=1`
`4sin^-1x=pi-cos^-1x`
Solve the following equation for x:
cot−1x − cot−1(x + 2) =`pi/12`, x > 0
Solve the following:
`cos^-1x+sin^-1 x/2=π/6`
`4tan^-1 1/5-tan^-1 1/239=pi/4`
Solve the following equation for x:
`cos^-1((x^2-1)/(x^2+1))+1/2tan^-1((2x)/(1-x^2))=(2x)/3`
Solve the following equation for x:
`tan^-1((x-2)/(x-1))+tan^-1((x+2)/(x+1))=pi/4`
Write the range of tan−1 x.
Write the value of sin−1 (sin 1550°).
Write the value of cos−1 \[\left( \tan\frac{3\pi}{4} \right)\]
Write the value ofWrite the value of \[2 \sin^{- 1} \frac{1}{2} + \cos^{- 1} \left( - \frac{1}{2} \right)\]
If x < 0, y < 0 such that xy = 1, then write the value of tan−1 x + tan−1 y.
Write the principal value of \[\cos^{- 1} \left( \cos\frac{2\pi}{3} \right) + \sin^{- 1} \left( \sin\frac{2\pi}{3} \right)\]
Write the principal value of \[\cos^{- 1} \left( \cos680^\circ \right)\]
Write the principal value of \[\sin^{- 1} \left\{ \cos\left( \sin^{- 1} \frac{1}{2} \right) \right\}\]
sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\] is equal to
If x < 0, y < 0 such that xy = 1, then tan−1 x + tan−1 y equals
If tan−1 3 + tan−1 x = tan−1 8, then x =
Find the domain of `sec^(-1)(3x-1)`.
The period of the function f(x) = tan3x is ____________.
