English

Write the Value of Cos2 - Mathematics

Advertisements
Advertisements

Question

Write the value of cos\[\left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right)\]

Advertisements

Solution

\[\text{Let }y = \cos^{- 1} \left( \frac{3}{5} \right)\]
\[ \Rightarrow \cos{y} = \frac{3}{5}\]

Now,

\[\cos^2 \left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right) = \cos^2 \left( \frac{1}{2}y \right)\]
\[ = \frac{\cos{y} + 1}{2} \left[ \because \cos2x = 2 \cos^2 x - 1 \right]\]
\[ = \frac{\frac{3}{5} + 1}{2}\]
\[ = \frac{\frac{8}{5}}{2}\]
\[ = \frac{4}{5}\]

∴ \[\cos^2 \left( \frac{1}{2} \cos^{- 1} \frac{3}{5} \right) = \frac{4}{5}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.15 [Page 117]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.15 | Q 22 | Page 117

RELATED QUESTIONS

Write the value of `tan(2tan^(-1)(1/5))`


Solve the equation for x:sin1x+sin1(1x)=cos1x


 

Show that:

`2 sin^-1 (3/5)-tan^-1 (17/31)=pi/4`

 

 

Find the domain of definition of `f(x)=cos^-1(x^2-4)`


Find the domain of `f(x)=cos^-1x+cosx.`


​Find the principal values of the following:

`cos^-1(sin   (4pi)/3)`


`sin^-1(sin  (7pi)/6)`


Evaluate the following:

`cos^-1(cos5)`


Evaluate the following:

`cosec^-1(cosec  (3pi)/4)`


Evaluate the following:

`cosec^-1{cosec  (-(9pi)/4)}`


Write the following in the simplest form:

`cot^-1  a/sqrt(x^2-a^2),|  x  | > a`


Write the following in the simplest form:

`tan^-1{(sqrt(1+x^2)-1)/x},x !=0`


Evaluate the following:

`sin(sin^-1  7/25)`

 


Evaluate the following:

`cot(cos^-1  3/5)`


Evaluate:

`cos{sin^-1(-7/25)}`


Evaluate:

`tan{cos^-1(-7/25)}`


Prove the following result:

`tan^-1  1/7+tan^-1  1/13=tan^-1  2/9`


Find the value of `tan^-1  (x/y)-tan^-1((x-y)/(x+y))`


Solve the following equation for x:

tan−1(x + 1) + tan−1(x − 1) = tan−1`8/31`


Solve the following equation for x:

`tan^-1  x/2+tan^-1  x/3=pi/4, 0<x<sqrt6`


Solve the following equation for x:

`tan^-1((x-2)/(x-4))+tan^-1((x+2)/(x+4))=pi/4`


Sum the following series:

`tan^-1  1/3+tan^-1  2/9+tan^-1  4/33+...+tan^-1  (2^(n-1))/(1+2^(2n-1))`


`sin^-1  5/13+cos^-1  3/5=tan^-1  63/16`


If `cos^-1  x/2+cos^-1  y/3=alpha,` then prove that  `9x^2-12xy cosa+4y^2=36sin^2a.`


`tan^-1  2/3=1/2tan^-1  12/5`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


If `sin^-1  (2a)/(1+a^2)-cos^-1  (1-b^2)/(1+b^2)=tan^-1  (2x)/(1-x^2)`, then prove that `x=(a-b)/(1+ab)`


Prove that

`sin{tan^-1  (1-x^2)/(2x)+cos^-1  (1-x^2)/(2x)}=1`


Solve the following equation for x:

`tan^-1  1/4+2tan^-1  1/5+tan^-1  1/6+tan^-1  1/x=pi/4`


Solve the following equation for x:

`2tan^-1(sinx)=tan^-1(2sinx),x!=pi/2`


Prove that:

`tan^-1  (2ab)/(a^2-b^2)+tan^-1  (2xy)/(x^2-y^2)=tan^-1  (2alphabeta)/(alpha^2-beta^2),`   where `alpha=ax-by  and  beta=ay+bx.`


Write the value of cos \[\left( 2 \sin^{- 1} \frac{1}{2} \right)\]


If x < 0, y < 0 such that xy = 1, then write the value of tan1 x + tan−1 y.


sin\[\left[ \cot^{- 1} \left\{ \tan\left( \cos^{- 1} x \right) \right\} \right]\]  is equal to

 

 

The number of real solutions of the equation \[\sqrt{1 + \cos 2x} = \sqrt{2} \sin^{- 1} (\sin x), - \pi \leq x \leq \pi\]


If \[3\sin^{- 1} \left( \frac{2x}{1 + x^2} \right) - 4 \cos^{- 1} \left( \frac{1 - x^2}{1 + x^2} \right) + 2 \tan^{- 1} \left( \frac{2x}{1 - x^2} \right) = \frac{\pi}{3}\] is equal to

 


If > 1, then \[2 \tan^{- 1} x + \sin^{- 1} \left( \frac{2x}{1 + x^2} \right)\] is equal to

 


If 2 tan−1 (cos θ) = tan−1 (2 cosec θ), (θ ≠ 0), then find the value of θ.


If \[\tan^{- 1} \left( \frac{1}{1 + 1 . 2} \right) + \tan^{- 1} \left( \frac{1}{1 + 2 . 3} \right) + . . . + \tan^{- 1} \left( \frac{1}{1 + n . \left( n + 1 \right)} \right) = \tan^{- 1} \theta\] , then find the value of θ.


Find the real solutions of the equation
`tan^-1 sqrt(x(x + 1)) + sin^-1 sqrt(x^2 + x + 1) = pi/2`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×