English

​Find the Principal Values of the Following: `Cos^-1(Tan (3pi)/4)` - Mathematics

Advertisements
Advertisements

Question

​Find the principal values of the following:

`cos^-1(tan  (3pi)/4)`

Advertisements

Solution

Let `cos^-1(tan  (3pi)/4)=y`

Then, 

`cosy=tan  (3pi)/4`

We know that the range of the principal value branch is [0,pi]

thus, 

`cosy=tan  (3pi)/4=-1=cos(pi)`

`=>y=piin[0,pi]`

Hence, the principal value of `cos^-1(tan  (3pi)/4)` is  π.

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Inverse Trigonometric Functions - Exercise 4.02 [Page 10]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.02 | Q 4.4 | Page 10

RELATED QUESTIONS

If sin [cot−1 (x+1)] = cos(tan1x), then find x.


If (tan1x)2 + (cot−1x)2 = 5π2/8, then find x.


`sin^-1(sin  (7pi)/6)`


`sin^-1(sin  (17pi)/8)`


Evaluate the following:

`cos^-1{cos(-pi/4)}`


Evaluate the following:

`cos^-1{cos  ((4pi)/3)}`


Evaluate the following:

`cos^-1(cos4)`


Evaluate the following:

`cos^-1(cos5)`


Evaluate the following:

`cos^-1(cos12)`


Evaluate the following:

`sec^-1(sec  (13pi)/4)`


Evaluate the following:

`cosec^-1(cosec  (11pi)/6)`


Evaluate the following:

`cot^-1{cot (-(8pi)/3)}`


Write the following in the simplest form:

`cot^-1  a/sqrt(x^2-a^2),|  x  | > a`


Write the following in the simplest form:

`tan^-1sqrt((a-x)/(a+x)),-a<x<a`


Write the following in the simplest form:

`sin^-1{(x+sqrt(1-x^2))/sqrt2},-1<x<1`


Evaluate:

`cos(tan^-1  3/4)`


`5tan^-1x+3cot^-1x=2x`


Prove the following result:

`tan^-1  1/7+tan^-1  1/13=tan^-1  2/9`


Find the value of `tan^-1  (x/y)-tan^-1((x-y)/(x+y))`


Solve the following equation for x:

tan−1(x + 1) + tan−1(x − 1) = tan−1`8/31`


Evaluate: `cos(sin^-1  3/5+sin^-1  5/13)`


Solve the following:

`sin^-1x+sin^-1  2x=pi/3`


Evaluate the following:

`sin(1/2cos^-1  4/5)`


`tan^-1  1/4+tan^-1  2/9=1/2cos^-1  3/2=1/2sin^-1(4/5)`


`tan^-1  2/3=1/2tan^-1  12/5`


`sin^-1  4/5+2tan^-1  1/3=pi/2`


`2sin^-1  3/5-tan^-1  17/31=pi/4`


`2tan^-1  1/5+tan^-1  1/8=tan^-1  4/7`


`4tan^-1  1/5-tan^-1  1/239=pi/4`


Find the value of the following:

`tan^-1{2cos(2sin^-1  1/2)}`


Write the value of sin−1

\[\left( \sin( -{600}°) \right)\].

 

 


Write the value of cos\[\left( 2 \sin^{- 1} \frac{1}{3} \right)\]


Write the value of sin1 (sin 1550°).


Write the value of sin−1 \[\left( \cos\frac{\pi}{9} \right)\]


Write the value of \[\tan^{- 1} \frac{a}{b} - \tan^{- 1} \left( \frac{a - b}{a + b} \right)\]


Evaluate: \[\sin^{- 1} \left( \sin\frac{3\pi}{5} \right)\]


Write the principal value of \[\cos^{- 1} \left( \cos680^\circ  \right)\]


Write the value of  \[\tan^{- 1} \left( \frac{1}{x} \right)\]  for x < 0 in terms of `cot^-1x`


The value of tan \[\left\{ \cos^{- 1} \frac{1}{5\sqrt{2}} - \sin^{- 1} \frac{4}{\sqrt{17}} \right\}\] is

 


The value of  \[\sin\left( 2\left( \tan^{- 1} 0 . 75 \right) \right)\] is equal to

 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×