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Evaluate the Following: `Tan^-1(-1/Sqrt3)+Tan^-1(-sqrt3)+Tan^-1(Sin(-pi/2))` - Mathematics

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Question

Evaluate the following:

`tan^-1(-1/sqrt3)+tan^-1(-sqrt3)+tan^-1(sin(-pi/2))`

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Solution

`tan^-1(-1/sqrt3)+tan^-1(-sqrt3)+tan^-1(sin(-pi/2))`

= `tan^-1(-1/sqrt3)+tan^-1(-sqrt3)+tan^-1(sin(-pi/2))`

`=tan^-1(-1/sqrt3)+tan^-1(-sqrt3)+tan^-1(-1)`

`=-tan^-1(1/sqrt3)-tan^-1(sqrt3)-tan^-1(1)`

`=-tan^-1(tan  pi/6)-tan^-1(pi/3)-tan^-1(pi/4)`

`=-pi/6-pi/3-pi/4`

`=-(3pi)/4`

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Chapter 4: Inverse Trigonometric Functions - Exercise 4.03 [Page 14]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 4 Inverse Trigonometric Functions
Exercise 4.03 | Q 3.2 | Page 14
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