Definitions [14]
Electromagnetism is the branch of physics that studies the relationship between electric charges, electric current, and magnetic effects.
When both electric and magnetic fields act on a charge, the total force is called the Lorentz force.
The force experienced by a moving charge in the presence of a magnetic field, which depends on charge q, velocity v and magnetic field B, and which is opposite in direction on a negative charge compared to a positive charge, is called the magnetic force.
Define ampere.
Current passed through each of the two infinitely long parallel straight conductors kept at a distance of one meter apart in vacuum causes each conductor to experience a force of 2 × 10-7 newton per meter length of the conductor.
A long solenoid is a coil whose length is much greater than its radius, producing a uniform magnetic field inside and nearly zero field outside.
OR
A solenoid is a long helical coil of insulated wire with many closely spaced turns, whose length l is much greater than its radius R (i.e., l ≫ R), such that it produces a strong, uniform magnetic field inside and a negligible field outside.
The ampere is that constant current which, when maintained in each of two infinitely long, straight, parallel conductors of negligible circular cross-section, placed 1 metre apart in a vacuum, produces a force of 2 × 10−7 N per metre of length between them.
The rotational effect experienced by a current-carrying loop placed in a uniform magnetic field is called torque.
A vector quantity that measures the strength and orientation of a current loop as a magnetic source is called the magnetic dipole moment.
The current required to produce a unit deflection (1 division) on the scale.
Define the term ‘current sensitivity’ of a moving coil galvanometer.
The current sensitivity of a galvanometer is defined as the deflection produced in the galvanometer when a unit current flows through it.
Mathematically, it can be given by:
IS = `(NBA)/k`
Where k is the couple per unit twist.
Current sensitivity is defined as the deflection e per unit current.
A Moving Coil Galvanometer (MCG) is a sensitive electromagnetic instrument used to detect and measure small electric currents (of the order of microamperes to milliamperes) by measuring the deflection of a current-carrying coil placed in a uniform magnetic field.
Deflection produced per unit current.
Deflection produced per unit voltage.
An instrument used to measure the potential difference between two points in an electrical circuit, always connected in parallel with the component across which the voltage drop is to be measured, is called a voltmeter.
Formulae [17]
Maximum magnetic force (when v ⊥ B): Fmax = qv B
\[\vec F\] = q(\[\vec E\] + \[\vec v\] × \[\vec B\])
Vector Form: \[\vec F\] = q(\[\vec v\] × \[\vec B\])
Magnitude Form: F = qv B sin θ
Where:
- q = charge on the particle
- v = speed of the particle
- B = magnetic field strength
- θ = angle between \[\vec v\] and \[\vec B\]
\[\vec{E}=\frac{1}{4\pi\varepsilon_0}\frac{Q}{r^2}\hat{r}\]
Combining the four dependencies: dB ∝ \[\frac {I dl sin θ}{r^2}\]
Introducing the constant of proportionality \[\frac {μ_0}{4π}\]:
\[dB=\frac{\mu_0}{4\pi}\cdot\frac{Idl\sin\theta}{r^2}\]
\[{d\vec{B}=\frac{\mu_0}{4\pi}\cdot\frac{Id\vec{l}\times\hat{r}}{r^2}=\frac{\mu_0}{4\pi}\cdot\frac{Id\vec{l}\times\vec{r}}{r^3}}\]
For a finite conductor, integrate over the entire length:
\[{\vec{B}=\frac{\mu_0I}{4\pi}\int\frac{d\vec{l}\times\hat{r}}{r^2}}\]
\[\vec{B}=\frac{\mu_0IR^2}{2(x^2+R^2)^{3/2}}\hat{i}\]
Where:
- I = current
- R = radius of loop
- x = distance from centre along axis
- μ0 = permeability of free space
F = IL × B
B = μ0nI
Where:
- μ0 = permeability of free space
- n = number of turns per unit length
- I = current
\[F=\frac{\mu_0I_1I_2}{2\pi d}\times l\]
Per unit length:
\[\frac{F}{l}=\frac{\mu_0I_1I_2}{2\pi d}\]
Force acts along the line joining the wires
\[\tau=NIAB\sin\theta\]
Also written as:
\[\vec{\tau}=\vec{m}\times\vec{B}\]
\[m=NIA\]
VS = \[\frac{\phi}{V}=\frac{NAB}{CG}\]
where G = resistance of the galvanometer coil.
Unit: div/V
k = \[\frac{I}{\phi}=\frac{C}{NAB}\]
k is the reciprocal of current sensitivity. A galvanometer with a smaller figure of merit is more sensitive.
CS = \[\frac{\phi}{I}=\frac{NAB}{C}\]
Unit: div/A or div/μA
Theorems and Laws [8]
If we stretch the index finger, middle finger and thumb of the left hand mutually perpendicular to each other such that the index finger points along the direction of the magnetic field and the middle finger along the direction of current (moving charge), then the thumb represents the direction of the force F experienced by the moving charge.
The magnitude of magnetic induction (dB) at a point due to a small element of current carrying conductor is:
(i) directly proportional to current (dB ∝ I),
(ii) directly proportional to length of element (dB ∝ dl),
(iii) directly proportional to sine of angle between element and line joining its centre to the point (dB ∝ sin θ),
(iv) inversely proportional to square of distance (dB ∝ 1/r²).
Applications
- Magnetic field at centre of circular coil.
- Magnetic field on axis of the coil.
- Magnetic field at a distance from a straight current-carrying conductor.
Statement
The line integral \[\oint\vec{B}\cdot d\vec{l}\] taken around any closed loop equals μ₀ times the net steady current passing through the loop.
Proof (for a long straight wire)
-
Consider an infinitely long straight wire carrying current I.
-
By Biot–Savart law, field at distance r:
B = \[\frac{\mu_0I}{2\pi r}\] -
Choose a circular Amperian loop of radius r, concentric with the wire.
-
By symmetry, B is constant in magnitude and tangential (parallel to \[d\vec l\]) everywhere:
\[\oint\vec{B}\cdot d\vec{l}=B\oint dl\] = B(2πr) -
Substituting B:
\[\oint\vec{B}\cdot d\vec{l}=\frac{\mu_0I}{2\pi r}(2\pi r)\] = μ0I
Conclusion
\[\oint\vec{B}\cdot d\vec{l}=\mu_0I\]
The result is independent of the loop's radius, confirming the law's validity.
Step 1: Torque due to current (Deflecting Couple):
- When current I flows through a coil of N turns, area A, in a field B: τdeflecting = N I A B (Since radial field: sin90° = 1)
Step 2: Restoring Torque (Spring):
- The phosphor-bronze strip/spring opposes the deflection. If ϕ is the angular deflection and C (or k) is the torsional constant of the spring, τrestoring = Cϕ
Step 3: Equilibrium Condition:
- At equilibrium, deflecting torque = restoring torque: NIAB = Cϕ
Step 4: Current–Deflection Relationship:
- ϕ = (\[\frac {NAB}{C}\])I
- ϕ ∝ I
The deflection is directly proportional to the current. This makes the scale linear and uniform.
Statement
In any closed loop of an electric circuit, the algebraic sum of all changes in potential is zero.
Derivation
Consider a charge moving around a closed loop. After completing one full loop, the charge returns to its starting point. Since electric potential depends only on position, the net change in potential over a complete loop must be zero.
Therefore, in a closed loop,
If a loop contains cells and resistors, then the total emf supplied by the sources is equal to the total potential drop across the resistors. Thus,
Conclusion
Kirchhoff's Second Law is a direct consequence of the conservation of energy.
At any junction, the sum of currents entering = the sum of currents leaving.
Example: I1 + I3 = I2 + I4. Based on conservation of charge.
The algebraic sum of potential differences in a closed loop is zero.
Based on conservation of energy.
Statement
At any junction in an electric circuit, the sum of currents entering the junction is equal to the sum of currents leaving the junction.
Derivation
When the current in a circuit is steady, charge does not accumulate at any junction. Therefore, the amount of charge entering the junction per second must be equal to the amount of charge leaving the junction per second.
If currents I1 and I2 enter a junction and currents I3 and I4 leave it, then
or
Hence,
Conclusion
Kirchhoff's First Law is a direct consequence of the conservation of charge.
Key Points
- Kirchhoff's laws are used for complex circuits.
- Kirchhoff's First Law: Total current entering a junction = total current leaving a junction.
- Kirchhoff's Second Law: Total potential rise in a closed loop = total potential drop in the loop.
- KCL is based on conservation of charge.
- KVL is based on conservation of energy.
- Mathematical forms are ∑I = 0 and ∑V = 0.
- The correct sign convention is essential in numericals.
Important Questions [94]
- Find the Condition Under Which the Charged Particles Moving with Different Speeds in the Presence of Electric and Magnetic Field Vectors Can Be Used to Select Charged Particles of a Particular Speed.
- Two Identical Circular Wires P and Q Each of Radius R and Carrying Current ‘I’ Are Kept in Perpendicular Planes Such that They Have a Common Centre as Shown in the Figure.
- The Motion of Copper Plate is Damped When It is Allowed to Oscillate Between the Two Poles of a Magnet. What is the Cause of this Damping?
- Show with the Help of a Diagram How the Force Between the Two Conductors Would Change When the Currents in Them Flow in the Opposite Directions?
- Sketch a Schematic Diagram Depicting Oscillating Electric and Magnetic Fields of an Em Wave Propagating Along + Z-direction ?
- If an Electric Field → E is Also Applied Such that the Particle Continues Moving Along the Original Straight Line Path, What Should Be the Magnitude and Direction of the Electric Field → E ?
- A Point Charge Q Moving with Speed V Enters a Uniform Magnetic Field B that is Acting into the Plane of the Paper as Shown. What is the Path Followed by the Charge Q and in Which Plane Does It Move?
- Two Identical Coils P and Q Each of Radius R Are Lying in Perpendicular Planes Such that They Have a Common Centre.
- Two Long Straight Parallel Conductors Carrying Steady Currents I1 And I2 Are Separated by a Distance 'D'. Explain Briefly, with the Help of a Suitable Diagram, How the Magnetic Field Due to One
- Depict the Behaviour of Magnetic Field Lines in the Presence of a Diamagnetic Material?
- Briefly explain various ways to increase the strength of the magnetic field produced by a given solenoid.
- A Long Straight Wire of a Circular Cross-section of Radius ‘A’ Carries a Steady Current ‘I’. the Current is Uniformly Distributed Across the Cross-section. Apply Ampere’S Circuital Law to Calculate
- Write Maxwell'S Generalization of Ampere'S Circuital Law.
- Using Ampere’S Circuital Law, Obtain the Expression for the Magnetic Field Due to a Long Solenoid at a Point Inside the Solenoid on Its Axis ?
- State Ampere’s circuital law.
- Electron Drift Speed is Estimated to Be of the Order of mm s^−1. Yet Large Current of the Order of Few Amperes Can Be Set up in the Wire. Explain Briefly.
- Read the following paragraph Consider the experimental set-up shown in the figure. Explain the reason for the jumping of the ring when the switch is closed in the circuit.
- A long straight wire of radius 'a' carries a steady current 'I'. The current is uniformly distributed across its area of cross-section. The ratio of the magnitude of magnetic field
- Write Maxwell'S Generalization of Ampere'S Circuital Law
- How is the Magnetic Field Inside a Given Solenoid Made Strong?
- An Observer to the Left of a Solenoid of N Turns Each of Cross Section Area 'A' Observes that a Steady Current I in It Flows in the Clockwise Direction. Depict the Magnetic Field Lines Due to the Solenoid Specifying Its Polarity and Show that It Acts as a Bar Magnet of Magnetic Moment M = NIA
- Obtain the Expression for Mutual Inductance of a Pair of Long Coaxial Solenoids
- Two Long Coaxial Insulated Solenoids, S1 and S2 of Equal Lengths Are Wound One Over the Other as Shown in the Figure. a Steady Current "I" Flow Thought the Inner Solenoid S1 to the Other End B, Which is Connected to the Outer Solenoid S2 Through Which the Same Current "I" Flows in the Opposite Direction So as to Come Out at End A.
- Define Self-inductance of a Coil.
- A Wire Ab is Carrying a Steady Current of 12 a and is Lying on the Table. Another Wire Cd Carrying 5 a is Held Directly Above Ab at a Height of 1 Mm.
- Obtain an Expression for the Energy Stored in a Solenoid of Self-inductance ‘L’ When the Current Through It Grows from Zero to ‘I’.
- Obtain the Expression for the Magnetic Energy Stored in an Inductor of Self-inductance L to Build up a Current I Through It.
- Derive an Expression for the Mutual Inductance of Two Long Co-axial Solenoids of Same Length Wound One Over the Other
- Derive the Expression for the Magnetic Field Due to a Solenoid
- A Wire Ab is Carrying a Steady Current of 10 a and is Lying on the Table. Another Wire Cd Carrying 6 a is Held Directly Above Ab at a Height of 2 Mm. Find the Mass per Unit Length of the Wire Cd
- A Wire Ab is Carrying a Steady Current of 6 a and is Lying on the Table. Another Wire Cd Carrying 4 a is Held Directly Above Ab at a Height of 1 Mm.
- Define Mutual Inductance Between Two Long Coaxial Solenoids. Find Out the Expression for the Mutual Inductance of Inner Solenoid of Length L Having the Radius R1
- Define the Term Self-inductance of a Solenoid
- Use this Law to Obtain the Expression for the Magnetic Field Inside an Air Cored Toroid of Average Radius 'r', Having 'n' Turns per Unit Length and Carrying a Steady Current I.
- In What Respect is a Toroid Different from a Solenoid?
- Draw and Compare the Pattern of the Magnetic Field Lines in the Two Cases ?
- Two long parallel wires kept 2 m apart carry 3A current each, in the same direction. The force per unit length on one wire due to the other is ______.
- Two Infinitely Large Plane Thin Parallel Sheets Having Surface Charge Densities σ1 And σ2 (σ1 > σ2) Are Shown in the Figure.
- The Figure Shows Three Infinitely Long Straight Parallel Current Carrying Conductors. Find the (I) Magnitude and Direction of the Net Magnetic Field at Point a Lying on Conductor 1
- Derive the Expression for Force per Unit Length Between Two Long Straight Parallel Current Carrying Conductors. Hence Define One Ampere.
- How Does One Understand this Motional Emf by Invoking the Lorentz Force Acting on the Free Charge Carriers of the Conductor?
- Answer the Following Question. Two Infinitely Long Straight Wire A1 And A2 Carrying Currents I and 2i Flowing in the Same Direction Are Kept' Distance Apart.
- Using the Concept of Force Between Two Infinitely Long Parallel Current Carrying Conductors, Define One Ampere of Current.
- Two Infinitely Long Straight Parallel Wires, '1' and '2', Carrying Steady Currents I1 and I2 in the Same Direction Are Separated by a Distance D. Obtain the Expression for the Magnetic Field `B`Due to the Wire '1' Acting on Wire '2'. Hence Find Out, with the Help of a Suitable Diagram,
- Two Long Straight Parallel Conductors 'A' and 'B', Carrying Steady Currents Ia And Ib Are Separated by a Distance D. Write the Magnitude and Direction of the Magnetic Field Produced by the Conductor
- Beams of electrons and protons move parallel to each other in the same direction. They ______.
- A Magnetised Needle of Magnetic Moment 4.8 × 10−2 Jt−1 is Placed at 30° with the Direction of Uniform Magnetic Field of Magnitude 3 × 10−2 T. Calculate the Torque Acting on the Needle.
- A Rectangular Loop of Wire of Size 4 Cm × 10 Cm Carries a Steady Current of 2 A. a Straight Long Wire Carrying 5 a Current is Kept Near the Loop as Shown. If the Loop and the Wire Are Coplanar, Find
- Assertion (A): The deflecting torque acting on a current-carrying loop is zero when its plane is perpendicular to the direction of the magnetic field. Reason (R): The deflecting torque
- A Rectangular Loop of Wire of Size 2.5 Cm × 4 Cm Carries a Steady Current of 1 A. a Straight Wire Carrying 2 a Current is Kept Near the Loop as Shown
- A Rectangular Loop of Wire of Size 2 Cm × 5 Cm Carries a Steady Current of 1 A. a Straight Long Wire Carrying 4 a Current is Kept Near the Loop as Shown.
- A planar loop of rectangular shape is moved within the region of a uniform magnetic field acting perpendicular to its plane. What is the direction and magnitude of the current induced in it?
- A Rectangular Loop of Size L × B Carrying a Steady Current I is Placed in a Uniform Magnetic Field → B . Prove that the Torque → τ Acting on the Loop is Give by → τ = → M × → B , Where → M
- A Square Loop of Side 'A' Carrying a Current I2 is Kept at Distance X from an Infinitely Long Straight Wire Carrying a Current I1 as Shown in the Figure. Obtain the Expression for the Resultant
- Define the Current Sensitivity of a Galvanometer ?
- Why Does a Galvanometer Show a Momentary Deflection at the Time of Charging Or Discharging a Capacitor?
- Obtain the Expression for Current Sensitivity of Moving Coil Galvanometer.
- A Galvanometer of Resistance G is Converted into a Voltmeter to Measure Upto V Volts by Connecting a Resistance R1 in Series with the Coil.
- Draw a Labelled Diagram of a Moving Coil Galvanometer. Describe Briefly Its Principle and Working.
- Why is It Necessary to Introduce a Cylindrical Soft Iron Core Inside the Coil of a Galvanometer?
- Increasing the Current Sensitivity of a Galvanometer May Not Necessarily Increase Its Voltage Sensitivity. Explain, Giving Reason.
- Why is it necessary to introduce a radial magnetic field inside the coil of a galvanometer?
- Can a galvanometer as such be used for measuring the current? Explain.
- With the Help of a Neat and Labelled Diagram, Explain the Principle and Working of a Moving Coil Galvanometer ?
- Define current sensitivity of a galvanometer.
- Why Does a Galvanometer When Connected in Series with a Capacitor Show a Momentary Deflection, When It is Being Charged Or Discharged?
- Write the Underlying Principle of a Moving Coil Galvanometer.
- Write Current Sensitivity of a Galvanomete S.I. Unit.
- Figure Shows Two Circuits Each Having a Galvanometer and a Battery of 3v.When the Galvanometers in Each Arrangement Do Not Show Any Deflection, Obtain the Ratio R1/R2.
- Explain, Giving Reasons, the Basic Difference in Converting a Galvanometer into (I) a Voltmeter and (Ii) an Ammeter?
- Draw a Labelled Diagram of a Moving Coil Galvanometer and Explain Its Working. What is the Function of Radial Magnetic Field Inside the Coil?
- In the Meter Bridge Experiment, Balance Point Was Observed at J with Aj = L.(I) The Values of R and X Were Doubled and Then Interchanged. What Would Be the New Position of Balance Point?
- State the Principle of the Working of a Moving Coil Galvanometer, Giving Its Labeled Diagram ?
- Outline the Necessary Steps to Convert a Galvanometer of Resistance Rg into an Ammeter of a Given Range ?
- State the Underlying Principle of Working of a Moving Coil Galvanometer. Write Two Reasons Why a Galvanometer Can Not Be Used as Such to Measure Current in a Given Circuit.
- State how a moving coil galvanometer can be converted into an ammeter.
- Explain the Significance of a Radial Magnetic Field When a Current-carrying Coil is Kept in It.
- Define the term ‘current sensitivity’ of a moving coil galvanometer.
- A galvanometer shows full-scale deflection for current Ig. A resistance R1 is required to convert it into a voltmeter of range (0 - V) and a resistance R2 to convert it
- How is current sensitivity increased?
- Use Kirchhoff'S Rules to Obtain Conditions for the Balance Condition in a Wheatstone Bridge.
- Using Kirchhoff’S Rules Determine the Value of Unknown Resistance R in the Circuit So that No Current Flows Through 4 ω Resistance. Also Find the Potential Difference Between a and D.
- Twelve wires each having a resistance of 3 Ω are connected to form a cubical network. A battery of 10 V and negligible internal resistance is connected across the diagonally opposite
- State Kirchhoff'S Rules for an Electric Network. Using Kirchhoff'S Rules, Obtain the Balance Condition in Terms of the Resistances of Four Arms of Wheatstone Bridge.
- State the Two Kirchhoff’S Rules Used in Electric Networks. How Are There Rules Justified?
- Obtain the condition for bridge balance in Wheatstone’s bridge.
- Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/5) Ω?
- Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/3) Ω?
- In the Given Circuit, Assuming Point a to Be at Zero Potential, Use Kirchhoff’S Rules to Determine the Potential at Point B.
- State Kirchhoff'S Rules and Explain on What Basis They Are Justified.
- Calculate the Value of the Resistance R in the Circuit Shown in the Figure So that the Current in the Circuit is 0.2 A. What Would B the Potential Difference Between Points a and B?
- The current is drawn from a cell of emf E and internal resistance r connected to the network of resistors each of resistance r as shown in the figure. Obtain the expression for the current draw from the cell and the power consumed in the network.
- Solve the Following Question. Using Kirchhoff’S Rules, Calculate the Current Through the 40 ω and 20 ω Resistors in the Following Circuit.
- Calculate the value of the resistance R in the circuit shown in the figure so that the current in the circuit is 0.2 A. What would b the potential difference between points B and E?
Concepts [12]
- Electromagnetism
- Magnetic force
- Motion in a Magnetic Field
- Magnetic Field Due to a Current-carrying Conductor: Biot-savart's Law
- Applications of Biot-Savart's Law > Magnetic Field at the Axis of a Circular Current-carrying Loop
- Ampere’s Circuital Law
- Solenoid
- Force Between Two Parallel Currents (Ampere’s Law)
- Torque on a Rectangular Current Loop in a Uniform Magnetic Field
- Circular Current Loop as a Magnetic Dipole
- Moving Coil Galvanometer
- Kirchhoff’s Laws
