English

If an Electric Field → E is Also Applied Such that the Particle Continues Moving Along the Original Straight Line Path, What Should Be the Magnitude and Direction of the Electric Field → E ? - Physics

Advertisements
Advertisements

Question

 If an electric field \[\vec{E}\] is also applied such that the particle continues moving along the original straight line path, what should be the magnitude and direction of the electric field \[\vec{E}\] ?

Advertisements

Solution

 The direction of the magnetic force is along negative Y-axis and so, the direction of electric force should be along the positive Y-axis to counter balance the magnetic force and charge particle will move in the straight line path.
Therefore, the direction of electric field is along the positive Y-axis and its magnitude is given by E = vB

shaalaa.com
Motion in a Magnetic Field
  Is there an error in this question or solution?
2015-2016 (March) Foreign Set 2

RELATED QUESTIONS

Two identical coils P and Q each of radius R are lying in perpendicular planes such that they have a common centre. Find the magnitude and direction of the magnetic field at the common centre of the two coils, if they carry currents equal to I and \[\sqrt{3}\] I respectively.


The motion of copper plate is damped when it is allowed to oscillate between the two poles of a magnet. What is the cause of this damping?


Two long straight parallel conductors carrying steady currents I1 and I2 are separated by a distance 'd'. Explain briefly, with the help of a suitable diagram, how the magnetic field due to one conductor acts on the other. Hence deduce the expression for the force acting between the two conductors. Mention the nature of this force.


Consider a long, straight wire of cross-sectional area A carrying a current i. Let there be n free electrons per unit volume. An observer places himself on a trolley moving in the direction opposite to the current with a speed  \[v = \frac{i}{\text{nAe}}\] and separation from the wire by a distance r. The magnetic field seen by the observer is very nearly  


A wire ab of length l, mass m and resistance R slides on a smooth, thick pair of metallic rails joined at the bottom as shown in figure. The plane of the rails makes an angle θ with the horizontal. A vertical magnetic field B exists in the region. If the wire slides on the rails at a constant speed v, show that \[B = \sqrt{\frac{mg R sin\theta}{v l^2 \cos^2 \theta}}\]


A charged particle moves through a magnetic field perpendicular to its direction. Then ______.


An electron having a charge e moves with a velocity v in X-direction. An electric field acts on it in Y-direction? The force on the electron acts in ______.

If an electron is moving with velocity `vecnu` produces a magnetic field `vec"B"`, then ______.


A deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let `r_d` and `r_alpha` be their respective radii of the circular path. The value of `(r_d)/(r_alpha)` is equal to ______.


A wire carrying current i has the configuration shown in figure. For the magnetic field to be zero at the centre of the circle, θ must be:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×