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Question
Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (11/5) Ω?
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Solution
Equivalent resistance, R' = `11/5` Ω
Consider the following combination of the resistors.
Equivalent resistance of the circuit is given by,
R' = `(2 xx 3)/(2 + 3) + 1`
= `6/5 + 1`
= `11/5` Ω
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