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Question
Calculate the value of the resistance R in the circuit shown in the figure so that the current in the circuit is 0.2 A. What would b the potential difference between points A and B?
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Solution
Apply Kirchhoff’s loop law in loop UVWXU:-
5(0.2) + R (0.2) + 10(0.2) = 6 − 2
⇒ R = 5Ω
VAB = VVW 5(0.2) = 1V
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