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Question
A point charge q moving with speed v enters a uniform magnetic field B that is acting into the plane of the paper as shown. What is the path followed by the charge q and in which plane does it move?
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Solution
When a charged particle having charge q moves inside a magnetic field \[\vec{B}\] with velocity v, it experiences a force `vecF=q(vecv xx vecB).`
When
\[\vec{v}\] is perpendicular to \[\vec{B}\] the force \[\vec{F}\] on the charged particle acts as the centripetal force and makes it move along a circular path.
The point charge travels in the plane perpendicular to both \[\vec{v}\] and \[\vec{B}\].
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