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Question
The angular frequency of revolution of a charged particle in a magnetic field is given by:
Options
\[\omega = \frac{m}{qB}\]
\[\omega = \frac{qB}{m}\]
\[\omega = \frac{qBm}{r}\]
\[\omega = \frac{q}{Bm}\]
MCQ
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Solution
Since v = ωr, substituting into \[r = \frac{mv}{qB}\] gives \[\omega r = \frac{qBr}{m}\], which simplifies to \[\omega = \frac{qB}{m}\]. This angular frequency is completely independent of the particle's speed and radius.
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