Advertisements
Advertisements
Question
- Define torque acting on a dipole of dipole moment \[\vec{p}\] placed in a uniform electric field \[\vec{E}\] Express it in the vector from and point out the direction along which it acts. Express it in the vector from and point out the direction along which it acts.
- What happens if the field is non-uniform?
- What would happen if the external field
\[\vec{E}\] is increasing (i) parallel to \[\vec{p}\] and (ii) anti-parallel to \[\vec{p}\]?
Advertisements
Solution
a. The torque `vecτ` acting on a dipole of dipole moment `vecp` in a uniform electric field `vecE` is given by:
`vecτ = vecpxxvecE`
Direction of Torque:
The direction of `vecτ` is perpendicular to the plane formed by `vecp` and `vecE`, as given by the right-hand rule for the cross product. This torque tends to rotate the dipole to align it with the field direction (i.e., make `vecp` point in the direction of `vecE`).
b. If the electric field is non-uniform, the dipole experiences:
- Torque (just like in the uniform field), and
- A net translational force.
This net force arises because the forces on the two charges (positive and negative) are no longer equal and opposite in a non-uniform field. As a result, the dipole experiences motion in addition to rotation.
c. Effect of Increasing Electric Field `vecE`:
- When `vecE` is Increasing Parallel to `vecp`:
- The potential energy of the dipole, given by `U = -vecp xx vecE`, becomes more negative.
- The dipole is already aligned with the field, and an increase in E further stabilizes this alignment.
- No torque acts because `vecp` is parallel to `vecE`; the dipole remains in equilibrium.
- When `vecE` is Increasing Anti-parallel to `vecp`:
- The potential energy becomes more positive, making the dipole increasingly unstable.
- A torque acts to rotate the dipole so that it aligns in the direction of the field.
- The dipole will tend to flip to align with the direction of increasing field.
RELATED QUESTIONS
An electric dipole of dipole moment`vecp` consists of point charges +q and −q separated by a distance 2a apart. Deduce the expression for the electric field `vecE` due to the dipole at a distance x from the centre of the dipole on its axial line in terms of the dipole moment `vecp`. Hence show that in the limit x>> a, `vecE->2vecp"/"(4piepsilon_0x^3)`
Depict the orientation of the dipole in (i) stable, (ii) unstable equilibrium in a uniform electric field.
Derive the expression for the electric potential due to an electric dipole at a point on its axial line.
Define dipole moment of an electric dipole. Is it a scalar or a vector?
Two particles, carrying charges −q and +q and and of mass m each, are fixed at the ends of a light rod of length a to form a dipole. The rod is clamped at an end and is placed in a uniform electric field E with the axis of the dipole along the electric field. The rod is slightly tilted and then released. Neglecting gravity, find the time period of small oscillations.
An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is ______.
The ratio of the weight of a man in a stationary lift and in a lift accelerating downwards with a uniform acceleration α is 3 : 2. The acceleration of the lift is:
Polar molecules are the molecules ______.
The electric potential V as a function of distance X is shown in the figure.
The graph of the magnitude of electric field intensity E as a function of X is ______.
In an electric dipole, what is the locus of a point having zero potential?
