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Question
- Define torque acting on a dipole of dipole moment \[\vec{p}\] placed in a uniform electric field \[\vec{E}\] Express it in the vector from and point out the direction along which it acts. Express it in the vector from and point out the direction along which it acts.
- What happens if the field is non-uniform?
- What would happen if the external field
\[\vec{E}\] is increasing (i) parallel to \[\vec{p}\] and (ii) anti-parallel to \[\vec{p}\]?
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Solution
a. The torque `vecτ` acting on a dipole of dipole moment `vecp` in a uniform electric field `vecE` is given by:
`vecτ = vecpxxvecE`
Direction of Torque:
The direction of `vecτ` is perpendicular to the plane formed by `vecp` and `vecE`, as given by the right-hand rule for the cross product. This torque tends to rotate the dipole to align it with the field direction (i.e., make `vecp` point in the direction of `vecE`).
b. If the electric field is non-uniform, the dipole experiences:
- Torque (just like in the uniform field), and
- A net translational force.
This net force arises because the forces on the two charges (positive and negative) are no longer equal and opposite in a non-uniform field. As a result, the dipole experiences motion in addition to rotation.
c. Effect of Increasing Electric Field `vecE`:
- When `vecE` is Increasing Parallel to `vecp`:
- The potential energy of the dipole, given by `U = -vecp xx vecE`, becomes more negative.
- The dipole is already aligned with the field, and an increase in E further stabilizes this alignment.
- No torque acts because `vecp` is parallel to `vecE`; the dipole remains in equilibrium.
- When `vecE` is Increasing Anti-parallel to `vecp`:
- The potential energy becomes more positive, making the dipole increasingly unstable.
- A torque acts to rotate the dipole so that it aligns in the direction of the field.
- The dipole will tend to flip to align with the direction of increasing field.
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