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Semiconductor Electronics - Materials, Devices and Simple Circuits
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- Detection of Amplitude Modulated Wave
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Definition: Solenoid
A long solenoid is a coil whose length is much greater than its radius, producing a uniform magnetic field inside and nearly zero field outside.
OR
A solenoid is a long helical coil of insulated wire with many closely spaced turns, whose length l is much greater than its radius R (i.e., l ≫ R), such that it produces a strong, uniform magnetic field inside and a negligible field outside.
Formula: Magnetic Field Inside a Long Solenoid
B = μ0nI
Where:
- μ0 = permeability of free space
- n = number of turns per unit length
- I = current
Construction
- A solenoid consists of a long cylindrical former (can be air-core, iron-core, or insulating rod).
- Enamelled copper wire is wound tightly in helical turns — insulation prevents short-circuiting between adjacent turns.
- Total turns: N; Length: l; Turns per unit length: n = \[\frac {N}{l}\]
- When current I flows → magnetic field is produced inside the windings.
Working Principle
- Each turn of the solenoid acts as a small current loop, producing a small magnetic field along the axis.
- In a long solenoid, the individual fields of each turn superpose constructively along the axis → uniform field inside.
- Outside the solenoid, fields from adjacent turns are in opposite directions and cancel → field ≈ 0 outside.
- The net effect: the solenoid behaves like a bar magnet with polarity determined by the direction of current (Right-Hand Thumb Rule).
Derivation of Magnetic Field Using Ampere's Law
Step 1 -S Set up the Amperian Loop:
Consider a rectangular Amperian loop abcd of length l, with side ab inside the solenoid (along the axis) and side cd outside.
Step 2 - Evaluate \[\oint\vec{B}\cdot d\vec{l}\] for each side:
| Side | Condition | Contribution |
|---|---|---|
| ab (inside, along axis) | \[\vec B\] || \[d\vec l\] | Bl |
| bc (perpendicular, inside→outside) | \[\vec B\] ⊥ \[d\vec l\] | 0 |
| cd (outside solenoid) | Boutside ≈ 0 | 0 |
| da (perpendicular, outside→inside) | \[\vec B\] ⊥ \[d\vec l\] | 0 |
\[\therefore\oint\vec{B}\cdot d\vec{l}\] = Bl
Step 3 - Calculate the enclosed current:
Number of turns inside loop = nl
∴ Total enclosed current = Ienc = n ⋅ l ⋅ I
Step 4 - Apply Ampere's Law:
Special Cases
| Location | Magnetic Field | Reason |
|---|---|---|
| Inside (ideal/infinite solenoid) | B = μ0nI | Superposition of all turns |
| At the ends (edge) | B = \[\frac {μ_0nI}{2}\] | Only half the turns contribute |
| Outside | B ≈ 0 | Cancellation of adjacent fields |
| With an iron core | B = μ0μrnI= | Core amplifies permeability |
Solenoid vs. Toroid
| Feature | Solenoid | Toroid |
|---|---|---|
| Shape | Long straight cylinder | Solenoid bent into a closed ring (doughnut) |
| Field inside | B = μ0nI (uniform) | B = \[\frac {μ_0NI}{2πr}\] (varies with r) |
| Field outside | B ≈ 0 (not exactly zero) | B = 0 (exactly zero) |
| Field at ends | B = \[\frac {μ_0nI}{2}\] | No ends (closed loop) |
| Uniformity | Uniform inside (away from ends) | Not uniform; depends on radius |
| Application | Electromagnets, relays, MRI | Inductors, transformers, RF circuits |
Applications
- MRI Machines — superconducting solenoids produce the powerful, stable magnetic field required for imaging.
- Electric Motors and Generators — solenoids create the rotating magnetic fields needed for motor operation.
- Solenoid Valves — used in hydraulic and pneumatic systems to control fluid flow (e.g., washing machines, car engines).
- Circuit Breakers / Relays — electromagnetic solenoids open/close switches on detecting fault current.
- Hard Disks and Loudspeakers — solenoid-based actuators position read/write heads and drive speaker cones.
Example
Given:
-
Length of solenoid: l = 0.5 m
-
Radius: r = 1 cm = 0.01 m
-
Total number of turns: N = 500
-
Current: I = 5 A
Step 1- Find turns per unit length (n):
Step 2 - Check if it qualifies as a long solenoid:
Since l/r = 50 ≫ 1, i.e., l ≫ r, the solenoid qualifies as a long solenoid, and we can use the standard formula.
Step 3 - Apply the formula B = μ0nI:
Answer: The magnetic field inside the solenoid is approximately 6.28 × 10−3 T (or ≈ 6.3 × 10−3 T).
Shaalaa.com | Magnetic field in Solenoid
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